https://youtu.be/HQED1U2DusM

Be careful you don't do something that shorts the coil somehow... that would suck, a lot of wire there... cool stuff though.

Quote from talisman on March 16th, 2018, 01:47 PM

I suppose I will know with bench tests but hear is a theory idea.

What is the optimal efficiency? Nearly all manufacturers of electric motors rate the efficiency at a particular level that is the maximum efficiency by in house standard test means.

Best 'generators' are at  98%, 2% as heat. The 98% using the Lenz effect to drag current.

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That is the cornerstone of volt to amp to ohm ratios.

Don't forget Russ,  we know that  elctrons are all around us,

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So if we define volts as potential if would be a hypothesis to consider that load amps resistance is realized potential.

Bearden says that the resistance creates electrons . If  we  short  a  circuit  with  a potential,  electrons flow throug it.

A standard equilateral triangle is 1 volt 1 amp 1 ohm
Why   using  ohm ?

I prefer  1V1A1S  as  you  told

and   better   1V1S  for  potential
and   1V1S1A   for   the   work   we  extract 

can   we  discuss    of that   on   one  of  your  video  lectures  ?  thx

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Then volts high amps low intuitively means hypothetically that there is available potential still to transform in the circuit.

if  a  circuit  is open to vacuum,  we could load ad infinitum, electrons would flow.
Classical   EM  relations   as   told  by  official science  are  shorted  to four  equations  relations are not helpful.

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The problem is how much additional load can be transferred to amps without the collapse of the magnetic field
but all of these need test to the specific dynamic electro mechanical configuration

>hat  is  the   magnetic  potential ?
--> B = μ.n.i(t)

so  B  is  B(t)

Knowing that:

--> W = 1/2( ε.E²+μB² )

and  what we  get is  transitoire   energy  field energy  in E ,

 Can  you   test   Newman  experiment    as   a   motor  -  to generate   coulombs   flux   I

• Charge the coil
• Pulse the  coil to activate the B field
• Do  it  such that the B field of magnet and  B field of coil cancel each other

it  is   testing  as  a generator   Newman  machine   without  the  magnet   

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Best 'generators' are at  98%, 2% as heat. The 98% using the Lenz effect to drag current

This is with the standard efficiency calculation. The charts for custom PM DC have their rated RPM and wattage
at those optimal speeds. These are for the motor alone.

In a motor generator I have seen videos where the motor and the generator are given the same calculation
with the mistake repeated where the resistance is assumed to be constant as a given parameter:

P=I^2R

Science Online motors and generators.

At the 5 minute mark the video educator uses this formula as a proof to debunk efforts at
motor generator technology.

I know that the resistance changes to speed and load and the premise is false.

He also discounts any possibility with simple looping implying there is no such thing as
a lenzless generator or a cycle recapture of waveform, parasitics etcetera (all the things
we work with in our effort); to him it's all a closed system with no recapture of energy..

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Then volts high amps low intuitively means hypothetically that there is available potential still to transform in the circuit.
Not exactly true in  our  pov:  if  a  circuit  is open to vacuum,  we could load ad infinitum, electrons would flow.
but the Classical elct relations are not helpful.

Exactly; but the main idea is that for the adding ad infitum there must be an increase in voltage potential in the process
that is to say the potential must increase in volts for levels higher ad infitum.

You have the idea of the standard triangle. It was to illustrate that the three sides change depending
on the volts amp and resistance ratio in a motor generator at various rpm and load. The triangle
changes if you freeze frame data points in time (like frames in a film for example). So the resistance
being constant being assumed in all motor generators is bunk.
 
.

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Bearden says that the resistance creates electrons . If  we  short  a  circuit  with  a potential,  electrons flow throug it.

He probably said this out of convenience. In peoples heads are the electrons of circuit theory. We are working both with and without
hardware circuits especially if you talk spark gap.

My thinking is:

Electrons are charged particle moving in a particular direction relative to an object.
Protons are moving but also are charged particles it the direction opposite.
Neutrons are the perfect math not charged state in other words static (electricity)
not moving in ether direction there is no difference in potential charge or time relation
to the circuit or mechanism under study.

This would imply a load brings inertia with some of the flow in the circuit as a hypothetical theory
if the math and definitions are unambiguous.

It makes perfect sense that the critic would use the most primitive example of a motor/generator to explain away the most advanced concepts they obviously do not understand. Not unlike saying my yard is flat .... therefore all yards must be flat and the Earth as well. It is a classic logical fallacy devoid of any sense of reason in my opinion.

My thinking is that I should concentrate more on my own creative solutions to any given problem and less on what others think. At the end of the day the winner is the person that makes something work not the person who does nothing and claims it cannot work.

I like those "people are awesome" youtube video's... these people are a shining example of everything a critic could never be.

Quote from Matt Watts on March 11th, 2018, 11:20 PM

That's the motor our buddy Er wants, based on the motors he has already built.  He has identified it to be "as close to perfect" possible.  The only exception is to center the coil on the axis like most window motors.  He suggested if one wanted to push really high voltages, build a bucket for the rotor and submerge the windings in oil.

Didn't John Bedini come up with the window motor after studying Newmans' work? catching up on my reading here...

I've been inspired by your work Russ, my daughters science project has me calculating windings... purchased 5lbs of 20awg and put a 2magnet wheel IN it... scope is very interesting. I'm mostly looking at this from the perspective you brought up about the current being in the same direction of input... I am using the inverted SSG ckt with my neg-2-neg mod to capitalize on that... very interesting stuff here. Keep up the good work.

Newman Motor

again, been out. but just trying to focuses.

minoly, yes its interesting.

here's one for you,

https://www.youtube.com/watch?v=6wmtoTCGDhI

Piero, thanks for taking the time to dive in to that.

It seems that with out the "boost" of momentum in to a flywheel to slam in to the next cycle... its quite "normal" as in the induced is less with more drag, and its more with over rotation. as it should be. so if we are going slow, I can drag it down more and draw more current from the battery, but producing more torque.

more testing to but the video i just posted is quite nice to watch... its in the right direction.

on time in that video is about ~160-170 degrees. no short, more to do...

~Russ

Looks like its coming along, keep up the good work.

Here is where the regular theory gets wacky. Showing negative amp and positive.

The question being: Is the average reflecting the total power?

Unconventional generator experimenters the last two years have pointed to the possibility that
electronic metering devices do not always accurately reflect the power for various reasons.
This possibly could be one of the reasons: 

There are two ways to see the math:

If there are negative amps and positive volts there is minus power or power literally being sucked out math wise.

So minus 2 amp plus three amp is one amp.


Is the negative amp the absence of power?

My bench says no not exactly a negative amp has power by analog gages the flow is opposite.

A remaining question then is: Is the negative power being used by the motor generator?


   

Quote from talisman on March 20th, 2018, 04:05 PM

Here is where the regular theory gets wacky. Showing negative amp and positive.

The question being: Is the average reflecting the total power?

Unconventional generator experimenters the last two years have pointed to the possibility that
the devices do not accurately reflect the power for various reasons. This possibly could be one of the
reasons: 


There are two ways to see the math:

If there are negative amps and positive volts there is minus power or power literally being sucked out math wise.

So minus 2 amp plus three amp is one amp.


Is the negative amp the absence of power?

My bench says no not exactly a negative amp has power by analog gages the flow is opposite.

A remaining question then is: Is the negative power being used by the motor generator?

correct.

torque output ( work done) , average power (consumption, if there is any) = efficiency.

It seems that the Boost this thing gets right at the start *Could produce all negtive current the rest of the cycle. as described by Hastings.

also note, if the power is switched fast ( bad brush contact) then the result is even further enhanced. although i haven't seen/tested this just yet. but it is from the result of others..

I have been thinking a lot about how the fast pulses could be adding in the system. but haven't had time to test anything yet.

~Russ

Russ does the new commentator have the same timing as the old one ?

Setup is looking more and more interesting.

"on time in that video is about ~160-170 degrees. no short, more to do... "

Really need to go slightly less on time I think... 

~Russ

Side note, 

With the coil conected to the siggnal genarator... 

I can rotate the magnet in the coil...

5V @ 70uA   = 350uW  ( micro watt).

Yes with 350 uW I can rotate the magnet lol

Pulling against gravity. 

Oh man I was laughing becuse it was messing up my test lol. 

~Russ

https://www.youtube.com/watch?v=zyRviYzdXdk

 In this update video I demonstrate how the battery resistance plays a major roll in how this system works. Even tho the battery is supplying the catalyst for the result we are seeing, the battery is also creating a "short" that is holding the magnet from going faster than it could. The "torque" I'm talking about in this video is not that great. you can however tell a big difference from the 100V to the 860V even tho the same 2ma is going through the coil when i'm holding it back.  However because the more battery's we add, the less resistance across the coil, the less drag the "short" has on the magnet. so there is a balance between the induction, the battery resistance and the "free spin" rotation it has. Don't forget we are playing with a "conventional closed circuit" here.

   ~Russ

Quote from ~Russ on March 21st, 2018, 02:33 PM

In this update video I demonstrate how the battery resistance plays a major roll in how this system works. Even tho the battery is supplying the catalyst for the result we are seeing, the battery is also creating a "short" that is holding the magnet from going faster than it could.

Adding a *load* is anything closed-circuit or T.E.M. The battery's resistance is the *load* to the circuit.

L.M.D. is open-circuit.

The Tesla Hairpin Circuit is actually an open-circuit. It uses a cap on each end of the stout bar.

Quote from haxar on March 21st, 2018, 06:12 PM

The Tesla Hairpin Circuit is actually an open-circuit. It uses a cap on each end of the stout bar.

Ah, but is it...?

A discharged capacitor has what for resistance?

A dielectric is an integral part of a resistor.  So therefore, what is a resistor exactly?

Hint, it's more than just Ohm's Law.

A cap has no resistance at the leads.

No bridge.

Same as a water cap.

Quote from Matt Watts on March 21st, 2018, 06:26 PM

Hint, it's more than just Ohm's Law.

Resistor != Capacitor

Quote from ~Russ on March 21st, 2018, 02:33 PM

https://www.youtube.com/watch?v=zyRviYzdXdk

 In this update video I demonstrate how the battery resistance plays a major roll in how this system works. Even tho the battery is supplying the catalyst for the result we are seeing, the battery is also creating a "short" that is holding the magnet from going faster than it could. The "torque" I'm talking about in this video is not that great. you can however tell a big difference from the 100V to the 860V even tho the same 2ma is going through the coil when i'm holding it back.  However because the more battery's we add, the less resistance across the coil, the less drag the "short" has on the magnet. so there is a balance between the induction, the battery resistance and the "free spin" rotation it has. Don't forget we are playing with a "conventional closed circuit" here.

   ~Russ

Hi, Russ.

So essentially a low-resistance battery would 'outrun' the rotational rate of the rotor, allowing the battery to continue pumping voltage into the coil and accelerating the rotor, whereas a high-resistance battery has a voltage dip which allows the induced momentum of the rotor (after the first 15 - 20 degrees of rotation) to induce current in the same direction as the applied current. Is that correct?

If so, could you set up a constant-current supply which mimics the batteries? The voltage would be high at open-circuit, it'd dip down just as the batteries do when the circuit is closed, and current would remain at a set maximum. The constant-current supply would allow you to experiment and tweak the initial voltage  and maximum current such that you can maximize the performance of the JWN replication.

Quote from haxar on March 21st, 2018, 06:46 PM

A cap has no resistance at the leads.

No bridge.

Same as a water cap.

A discharged cap has (effectively) no resistance. A charged capacitor, however, is another matter.

Electrical resistance is defined as a measure of the difficulty with which (in a typical circuit, electrons, but not necessarily so for all circuits, since current flow can be electrons, protons or ions) flow in a conductor.

A capacitor resists current flow successively more as it charges and energy is stored in the electric field of the dielectric between the capacitor plates.

Remember, as much charge flows into the capacitor as flows out (think of it like a fluid-filled sphere with a flexible membrane bisecting the interior, and a pipe on each side, to put it to a hydraulic analogy... pump fluid in one side and fluid must flow out the other side until membrane tension is great enough to equal the applied pressure, whereupon flow ceases), so a capacitor can be classified as a conductor.

So in effect, a capacitor is a combination of an electrostatic storage device and a variable resistor (the variance dependent upon the field polarization of the dielectric).

Quote from haxar on March 21st, 2018, 06:46 PM

A cap has no resistance at the leads.

Hmmm.  My ohm meter says otherwise.

Quote from Cycle on March 21st, 2018, 07:56 PM

A discharged cap has (effectively) no resistance. A charged capacitor, however, is another matter.

A resistor is a device that _________________.


Resistance is the key to this device, or should I say impedance.



Is kicking our ass.  We need to flip things around so that as resistance goes down, voltage AND current goes up.  We need conductance, not resistance.

Quote from Matt Watts on March 21st, 2018, 08:08 PM

A resistor is a device that _________________.

resists the flow of current.

And that's exactly what a capacitor does as it charges (that is the mechanism by which, after all, current flow decreases as the cap charges, speaking strictly on a quantum physics level). The mechanism for its doing so is different than that of a typical resistor (field polarization vs. heat emission due to electron collision), but the effect is the same.

Displacement current does not release heat, but conduction current does.  So a resistor is doing something in the dielectric that causes conduction current.  It's as if a resistor is actually a very leaky capacitor.

Now you've got it... except that the equation for capacitor stored energy is:
¹/₂ Q deltaV

So ¹/₂ of the applied energy goes to heat. Displacement current (as in charging a capacitor) does release heat.

That's why just dumping straight cap-to-cap, you'll always see at least ¹/₂ of your energy disappear.

Interestingly, an inductor and diode changes this relationship... the inductor 'spin-up' time changes the loss-rate of the capacitor (if you charge a cap from a voltage-following source, you'll see far less loss), and its conversion of kinetic energy (magnetic momentum) into potential energy (voltage) as it spins down allows more charge into the receiving cap.

Ideally, your inductor 'spin-up' time would exactly equal ²/₃ the charge time of the receiving cap (for the applied voltage)... that's how you get the nearest to 100% energy transfer (with equally sized caps).

In fact, in certain circumstances, you can utilize the kinetic energy of the magnetic field momentum in the inductor to create a 'vacuum' upstream... with a large enough receiving cap, this gives you >100% energy transfer.

That's the operating principle for the circuit I've posted about... it's only been run on a circuit simulator to date, though, so the real world may prove a bit more difficult to get it to work.