I removed L3 and L4, and the DC offset.(dc wasn't present in previous tests)

L2 tuned with 21nF.
65.27 kc/s is the impulse, but L2 is a octave higher. So 2 cycles per impulse. L2= 130,54 kc/s

yellow is L2 voltage, showing -3kV impulses

Now look at the amplitude of the L2 current in green.
After the impulse, at the second (free) oscillation, the current is larger.
Why?
Is it the mosfet switch is closed again, turning on the current supply?

What you also can see, is that the current amplification is not happening, at the moment of the impulse.
But that is usually happing in the L3 secondary coil. So, lets put that one in again.

With the same setup as previous post, I tuned down to 43.3kc/s which is the third subharmonic of L2.
Now, the ripples are present again. Is this due to the inteferrence of L1 resonant frequency and L2 resonant frequency?
power is higher due to the lower (L1 impulse) frequency

There is no amplification present. the waves are obviously damped. (loosing amplitude).
-3kV impulses again.

Just tested with L1 and L2 not being coupled. (no L3 L4 present)
even if L1 and L2 are not coupled, still the ripples occur.
The best way to get rid of it, is to keep the L2 series tuning capacitor small enough (which rises the resonant freqency).

So to get a pure impulse in the L2 primary coil, at lower frequencies, demands a higher inductance (more windings) L2 coil.
more windings, not only increases inductance, but also increases wire resistance, which influences the Q factor, and thus provides a longer duration impulse with a lower voltage, thus more power (higher voltage) needs to pumped into L1 to get a high voltage impulse again.

The Idea is to get it working below 100kc/s so I can get decent current probe readings.
Also, I want to make a new L3 secondary, with much more inductance (windings) than the L2 primary.
thus, more windings on L2, and more windings on L3.
I will keep using 1,5mm2 for L2,
but L3 will become 0,75mm2, while still keeping the copper mass of L2 and L3 equal.

The Idea, is to amplify voltage by resonance in L3, and amplify L3 current by the impulses of L2.
When both are amplified, L4 is again used to get them in phase.

ideally LMD resonance between L2 and L3 is again used, with the negative impulse on the V+max of L2.

L3 will have a small capacity, L2 will have a large capacity.

while testing today, I noticed the L3 coil was reverse connected, inside rim to ground.
And outside rim was connected to L4 outside rim.

If I can't get voltage and current of L4 back in phase, this might br the reason why.

https://www.bibliotecapleyades.net/tesla/esp_tesla_24.htm

played with the capacity of L2 and L3, and saw the L4 extra coil sometimes being in phase voltage and current, other times not.
The voltage of L4 can get insanely high, I was over 4kV with relative low inputs. That is is also cool, because when a resistive load is presented, a lot of voltage would still remain, being able to charge up a cap bank.
Need to try that... dinner time

the L2 L3 coils are capacitor plates.
when L2 discharges (by impulse) the L3 charges.

L3 coil by itself has a resonant frequency.

but I tune L3 down by adding parallel capacitor.
this lower frequency should be a sub harmonic of the L3 coil by itself.

then the impulse of L2 effects the L3 as a capacitor plate which gives a fast resonant rise at L3 frequency,
Which then is picked up by the lower sub harmonic.

giving a wave form with huge amplified current.

in practie: first measure resonant frequency of L3 without parallel capacitor (and extra coil connected and coupled).

then tune L3 down to sub harmonic with parallel cap. (I am guessing a odd harmonic but maybe should be even)

Its a bit like soldiers marching over a bridge, their frequency is a higher harmonic of the bridges resonant frequencie, which is able to bring the bridge into resonance.
Each stomp of their feet is an impulse.

I removed all capacity of L3 secondary, and measured the frequency of the ring: 529.1kc/c
the 5th sub harmonic is 105.82 kc/s So I added capacity parallel to L3 until I reached that frequency.
With a little fine tuning, the max rise was at 104.4 kc/s, no impulse (!) but 2 ripples.

Note that I could also tune a little above the 105.82, which gave also a rise, but with an impulse (and ripple).

L3 parallel tuned with 19.6nF at 104.4kc/s
SCR35 shows the L3 current and voltage , 15.5A and 1.26kV 90 degrees out of phase
SCR36 shows the L4 current and voltage, 5.5A 2.73kV 0 degrees IN PHASE (current probe has -10 degrees phase shift)
peak to peak.

Ideally half of the power, with impedance matching should be able to get out. but... thats theory.... first make it happen.

5.5 X 2730=15kW =10.6kW RMS, 50% out is 5kW rms
in theory...

power in is 1.17A X (2x 16.4V)=38.4W
that's 130 X more out than in.
IN THEORY.

For clarity, L2 primary has 134nF in series. Which gives a relative low resonant voltage rise (Yellow) but if I would measure the current of L2, it would be high.

now I wonder, dies this also apply to the primary coil? tune it ti a lower harmonic?
since l2 and L3 are equal size they should almost have the same frequency
but L1 and and l4 are different.

Since L2 and L3 each are equal, I would have expected them to be the same resonant frequency. But L1 (close coupled to L2) and L4 (close couple to L3) are different, so that wont work.

Instead I took a look at the voltage (yellow) and current (green) of the L2 primary.
L2 has a big series capacity, so the voltage is low (140Vpp), and the current is high 16.48A pp)

The impulse is totally invisible, as it is absorbed into the capacitor of the resonant system (?)
still 2 ripples are visible (2x -390V)

But most importantly, when the mosfet is switched off, there is no curretn amplification visible in L2.

I gave L3 46nF to tune it down to the 7th subharmonic, at 75,6 kc/s

I pumped in more power due to the lower frequency:
1,01A x 2 x 17,7V =35,8W

What I noticed, is again the phase shifting of L2, whereby the impulse now again is visible, but not at V max, its more close to the power max of L2, between V max and V zero.

now there is an impulse of -600V visible, but also 3,5 ripples of -200V. Actually, they look like sine waves. How can that be, why is the sine wave present on the negative side of L2 V only, I would have expected it centered on the middle of L2 V. with positive and negative swings... but the whole ac is negative relative to L2 V. The mystery continues.
I wonder, if the energy of L1 is oscillating, but the body diode wont open, as the voltage threshold is not crossed. But Cap at the Drain to ground, is 4uF , no way it is charged up to +200V.

L3 is at the 7th sub harmonic, and tuned by 46nF down to 75,6 kc/s
its  current is high. (but also pumping in more power)
L4 V= 1544V (orange) (I probed the L4 instead of the L3!)
L3 A= 13.78 A (green)
This means L3, has a lower voltage

Time to retune to the 4rd harmonic which is 132.3 kc/s

tuned L3 with 19.7 nF to 4th sub harmonic of 133.076kc/s
L2 (yellow) shows impulse and massive ripple) impulse has shorter duration than the ripple.
So Ripple cant be from L1? weird!

current and voltage of L3:
15.94App (green) and
1720Vpp (orange)
Which will make L4 go even higher in voltage( but lower in currnet, altough IN PHASE) lets check if that still is the case...
power in is high.
1.17A x 2x 16.4V=38.4W that's only 2 Watt more than the 7th subharmonic! but this higher frequency has more current and voltage.
Hej thats interesting!

-11 degrees phase shift on current probe at 133kc/s
green is current of L4 9.44A pp
orange= L4 voltage= 3836V pp
 :shocked:
36.2kW, which is 25.6 kW RMS, 50% is 12.8kW max output in THEORY.

OK... lets rectify this into DC, and load it, see what happens. use a high resistance load, to keep the voltage high.
I have some halogen lights... 230W 240V. maybe put 2 or 3 in series.

Why is current phase shifted between L3 and L4, is this due to the inductive load of L4 on L3? L4 has more windings, thinner wire (0,75) and larger length. They are not equal mass.
Is the inductive impedance of L4 phase shifting the current of L3?

L4 voltage is wrong
as it rides on top of the L3 voltage.
but still... a lot of potential power.

Quote

sometimes with DC power off (circuit on) i see the ripples barely sitting atop L2 & L3's flatline voltage, when power supply is at 0V OA. In these cases, "hint of ripple" happens right at MOSFET off, but slowly turning up voltage "slides" the ripple back toward end of "off" span & leading right up to "mosfet on". some reflection/polarization/reaction caused even by MOSFET breaking the circuit? can't make anything of it, hoped you might know if observation useful, Godspeed.

yes, the 12V circuit switches the mosfet by gate and source connection.
as the source and drain are connected to the coil, some of the gate charge might flow there due to capacitive coupling.
Thats my guess. I also see the signal on the coils, when I give 0V

AH>>> I did it again, instead of quoting, I modified the original message...
SORRY!

I just tested with rectifying L4 into DC caps, and halogen lamp 42W.
Resonance wasnt there any more, light did burn, but no proper sinewave.

I have diodes between cap and ground need to remove these

Quote from coldelectric on November 26th, 2021, 03:22 AM

AH>>> I did it again, instead of quoting, I modified the original message...
SORRY!

ha! with great power comes great responsibility. alas, rightly the Lord orders his domain, upon high, he sees thet it is good.

linz wire , coupling, choking, right hand rule  ,
Skin effect , bemf, capacitance , voltage - frequency
= single pancake with trifilar winding with blocking diodes.

Trust people saved the picture

Meyers Advanced Tesla

rather than stack it is linear

Quote from securesupplies on November 27th, 2021, 07:20 PM

linz wire , coupling, choking, right hand rule  ,
Skin effect , bemf, capacitance , voltage - frequency
= single pancake with trifilar winding with blocking diodes.

Trust people saved the picture

Meyers Advanced Tesla

rather than stack it is linear

why do you keep spamming my board with this? keep it on your own board please.
Or give a practical explanation why it is so important..

for example explain :
"unipolar cross over pulse train"

let's assume the dielectric field (voltage) is made of faraday tubes.

And the inside of these tubes is called counter space.

a magnetic field is a vortex is made up out of the rotating aether outside these faraday tubes. When the tubes move transversly they churn up the magnetic aether vortex. that is a spacial event, outside of the tubes.

Now the Impulses set up longitudinal flows inside the faraday tubes.

So first we need to set these tubes up. This is done by high voltage dc between primary and secondary coils that act as capacitor plates.

the impulse in the primary sets up a Longitudinal motion inside the tubes from primary into the secondary coil.

in the secondary the counter spacial stuff inside the tubes, becomes spacial again, it flows out of the tubes, in large sudden volumes. which amplify the spacial magnetic current as I have repeatedly seen.

So the counterspacial longitudinal current inside the tubes, becomes a spacial magnetic current, around the L3 secondary coil.

the inflow from spacial to counterspacial happens at the L1 coil, where the magnetic field is suddenly transformed into a dielectric impulse.

I will give the L2 primary coil, a much smaller capacity (less than 10nF instead of 135nF).
This will generate much less resonant current in the primary, and instead will create a very high resonant voltage. (different characteristic impedance)

Since the frequency will then also go up, I will tune the secondary L3 with a large capacity (again to a sub harmonic of L3). to get the frequency down again, to below 100kc/s ideally.
This will give L3 a large current.  L4 will again increase the voltage and decrease that current, but bring them in phase.

L3 and L4 are a bit like a center tap transformer winding. Maybe it could be interesting to see, what happens when L4 is counter rotated. (flipped over).

also interesting to see what happens if L4 is connected to ground by a series capacitor

Ideally the impulse again is on top of the positive voltage maximum of L2, which is made even more positive by the DC offset.
But, before, I saw the current amplification of L3, happening at the impulse at negative maximum.
This would be trouble some, as the high negative voltage maximum of L2, would diminish the positive dc offset. and the impulse could dip below zero voltage.  then the impulse could pass to ground by the diodes connected to L1.

the L3 current should again be amplified by the impulse.

the nice thing of this method of tuning, is the low current in L2 primary.
The weak magnetic field, will not be the dominant coupling to L3 secondary.
Instead, due to the high voltage, we have the dielectric coupling being dominant, and the dielectric induction by the impulse implosion of the dielectric field will then induce resonance in L3, whereby the longitudinal dielectric current, amplifies the transverse magnetic current in L3.

When a load is presented in L3, it will load down the magnetic field, which then couples back to the L2 primary, in a lesser way.
So instead of a magnetic coupling (L2 large capacity, high current) which would feel the L3 current being dragged down).
We now have the dielectric coupling between L2 and L3. due to L2 having a small magnetic field. thus it feels the magnetic field changes of L3 less.

the impulse placement has been all over the sine wave of L2 so, I still need to understand that also... Still haven't found the ideal placement of the impulse. but the biggest amplification of current in L3 seems to take place when the impulse is on the resonant power peak of L2. So somewhere in between the maximum and minimum of L2. This needs more testing.

What I also want to do, is remove the DC offset in L3, and ground it. then measure the current in the ground connection of L3.
I wonder, if the impulse that causes a current amplification in L3, gets the current out of the earth!

I made L2 series cap 10nF
I made L3 parallel cap 121nF
didnt use DC offset.
Tuned to first sub harmonic of L2, at 105.9 kc/s ( which is the 5th sub harmonmic of L3 by itself)
So 1 impulse per 2 cycles
input power is 1.14A x 2 x 31.7 = 72,276 (relativly high)

first sceenshot scr42 shows L2 voltage in yellow and L2 current in green
impulse is -3kV tuned to voltage minimum, positive current maximum is collapsed.

voltage sine wave is 1100V pp
current sine wave is 15.9 A pp WHY IS THAT SO HIGH?
even while the impulse is diminishing the current!
I need to get that current down, so 2nF instead of 10nF in series? and then tune to the third sub harmonic

second screenshot scr43 shows L3 voltage (orange) and current (green)
First... why has it got this strange woble, its not fixed on the zero axis.
voltage= big and small, total only 60V pp
current is around 7 A pp

edit:
current L2 is high, because the voltage of L2 is so high. energy is related to the square of the voltage, while capacity is linear. so try again, with smaller cap.

made L2 cap 3nF
L3 still the same 121nF
power in, 3.08A x2 x 11.6V =71,5W
frequency tuned way down to 37.4kc/s which is the frequency of L3 transverse resonance. L2 can be seen wobbling at its own frequency (around 98kc/s was the 4 cycles per impulse)
this is just a joke, but look at that energy inside L3... humongus
 scr44
L3 current in green... 32.83A pp (!)
L3 voltage in orange: 1232V pp (!)
huge....

scr45
L2 voltage in yellow (waving on L3)
L2 current in green (waving on L3 induced current)
L4 voltage in orange. (magnified to 2665V pp)

scr46
green is L4 current 3.5A pp
orange is L4 voltage.
See ... now they are not in phase.

seems L2 cap is now so small, and L3 cap is now so big, that they wont resonante at the same frequency anymore

colorado st[springs notes page 190 (185 of pdf) shows different extra coil setups.
fig 4 is noted as best, and it works best by having L3 as 1/4 wave, and L4 as half wave.
Then the series connection between L3 and L4 is raised in potential.

So L3 is like a whip antenna, grounded on one end, while the other end is vibrating. 1/4 wave.
but L4 is like a skipping rope. both ends are fixed, and the middle is vibrating. This I dont understand.
It would mean the open end of L4 would not vibrate? or...
The middle of L4 is not vibrating, but the ends are. yes. that makes sense.

then indeed L3 is amplified by L4 to huge voltages.

This also means, I should tap for power at the series connection of L3 and L4. (where tesla had a spark gap to ground)

Since L4 rides on top of the L4 wave, I wont expect the middel of L4 to stand still, but instead show less amplitude, then the ends of L4.

Also, for L4 to do this, it should have twice the mass of copper of L3? or twice the length? as only one half of L4 is the mirror of L3.