ok, since l2 will give the output, and we tume the impulse to the 7/8th point where both voltage and current are present.
It would be logical to have both voltage and current of L2 present at the best relation ship.

this is the characteristic impedance of L2.
the balance between resonant voltage and current.
We have a set amount of inductance for L2 as the weight must be equal to the L3 copper weight.

So we tune this by changing the series capacitor of L2.

if the cap is small, we will get high voltages but low currents, and high frequency.

if the cap is large we will get large currents and low voltages and low frequency.

so the perfect cap size would give max current and max voltage at the 7/8th point.

Then the impulse voltage is added to get maximum gain.

Since L1 and L2 are in series, the current that is in L1 also effects the current in L2. and vice versa

L3 is amplifying the L1 current, so L2 should also benefit from the L1 increased current.

very interesting.

When I did a load test With L4 close coupled to L2 a while back,
I noticed the lamp load was very consistent in power. not like it was when I was still loading L3.

this constant power from L2 affirms the resonant power concept of L2. at the 3/8th and 7/8th parts of the resonant sine.

the L2 and L3 coils are the plates of a high voltage dc capacitor, that is charged by giving L2 a positive DC offset.

this sets up a static dielectric field between L2 and L3.

when the negative impulse is introduced to L2, it discharges this coil capacitor.

L2 rapidly changes voltage from positive to zero voltage during the impulse.

L3 (as capacitor plate) wants to change with this changing dielectric field to keep it steady.But L3 is grounded.

So the dielectric field between L2 and L3 changes very fast, and looses its field strength during the impulse.

This discharge has no where to go.
and it is so fast, it creates a longitudinal aether displacement current.

If timed correctly it is picked up by the magnetic field (current).

but what is the correct timing, and how do we shift timing?

Timing is shifted by changing the coupling distance between L2 and L3 (while L3 is close coupled to L1).

so, where to time the impulse?
I always thought it was at V max where the current is zero.
zero current meant highest aether displacement speed,which from there on slows down.

but now by testing I am starting to see it is not at V max. and its also not at I max.
at max current the Aether movement stops and turns direction to speed up again. At I max the aether is maximum torqued like twisted bands of rubber.

then it should be after I max, where the aether volume is unwinding again and picking up speed.

And it should be before I=zero where V=Max.  before I=zero the speed is still increasing.

But that is not what I see.
What I see is the impulse is right after the zero current point and right before the I max point.

So the aether volume is spinning down, loosing momentum, loosing speed, and then the impulse gives it a kick. Some extra voltage to transform into more current.

pfew... logic. it never is as nature shows us. logic is only good to analyse collected data, not to predict future results

the problem with this picture is that crossing point doesn't have to be on 3/8th or 7/8th.

that only occurs when the current and voltage sine waves are equal size.

But what is equal size?
1A=1000V? no that doesn't work
it is dependend on the coil dimensions.
is it a pancake coil? is it a solenoid?

how tight are the windings?....

what is the ideal characteristic impedance?

what is the ideal balance between capacity and inductance?

How much capacity should I add to get it right?

I know from experience that the feedback system works best if L3 has a bit bigger capacity then L2 has.

But how big should the L2 capacity be?

If its to big there will be more current than voltage (and low frequency)
if it is to small there will be less current and more voltage (and high frequency)

What is ideal?
I know how to tune the impulse to the right point, but how do I set the right amount of capacity?

I guess by looking at how much the current is amplified?
pfffff.
so much guess work...
still today I had 25A pp again in L3. That is a lot. and L3 did not get hot. thats strange.

ok enough for now.

ok crossing point is only changing in visual graphs.
Max power point is always at 1/2 current and 1/2 voltage points at 3/8ths and 7/8ths of the wave form.

only thing that matters is the impulses amplify current.
the impulses are fast, so it would make sense to use high currents to get best results.

important is to tune the distance between L2 and L3, so that the impulses are on the 7/8th of L2 voltage sine, giving max current of L3.

I realize its not the 1/2 voltage and current point.
it's the square root of 2
0.707

in the graph, the green blocks represent the time where there is power in a resonant coil.
As in the green area's the voltage and current are both present in the same polarity

this is in balance, with the not green area's, where current and voltage are opposing.

This balance makes it so that the coil doesn't produce real power.

With diodes the green parts can be taken out, by rectification.

But that's not the point.

The green power area's can be amplified, by the addition of the impulse on the 3/8 and 7/8th points.

This added impulse voltage makes the power increase.
This would be best demonstrated with a radiant halfbridge circuit, that can produce both polarity impulses.

As posted before, to get the impulses on that point, the distance between L2 and L3 needs to be tuned (and max current L3)

1,47A 2x23.1V dc input power
Fres 81kc/s
L2 L3 distance= around 28mm (which is also the inner hole radius of the coils, which is smaller than phi ratio).

I tuned the spike at the 7/8 point.

This demands a higher input voltage, to get a decent impulse. so I will need to tune down in frequency by increasing L3 and L2 tuning capacitors. this will increase the current in L1, and give a larger voltage impulse.
I want a 3kV impulse.

since L3 is still much larger then L2 in ampliftude, I think making L3 even more larger in capacity then L2, would make sense, also with the cap discharge in mind.

2 realisations.

power is consumed with positive voltage and positive current

power is generated with positive voltage and negative current (or vice versa)

L2 output needs to be looked at and see where the impulse timing should be for max power.

L4 close coupled to L2 and l4 dc rectified with resistance load for power calculations

Equal amplitude for the L2 current. ignoring input power. just comparing impulse position vs output power

I added L4 to L2, close coupled, on the bottom of the stack, so now its
L1 L3----L2 L4

L2 now needs more tuning capacity to be intune again, haven't done it, but first test confirmed it. no perfect sine on L2, due to not enough series  capacity.

Lamp works. I grounded L4 for now, as I need 2 more diodes to fully rectify L4. (L4 cant be grounded with L2 having 3kV DC offset).

So I need to add diodes, and tune L2 again. probably now it will have equal capacity to L3, if so I will make them both 61nF to get the frequency as low as possible.

the half bridge idea still is in the back of my mind, but first I want to play out this setup.

now with L4 close coupled to L2,
L2 is 61nF and L3= 53nF

L4 loaded, increases the impedance of L2, which dampens the resonant sine wave somewhat, as expected.
But the impulse is still just as fast just a bit more that 400nS

I need to place the coils a bit nearer together to get the impulse on the 7/8th

another test, coils at 23mm distance (half turn less then before)
input power= 1,3A 2x20.6V=53.56W
F=80,8kc/s
42W lamp loaded on L4, measured 133mA 116,25V dc =15.46W
impulse =-1690V slightly less then 400nS duration
L3 (orange)= 537Vpp L3 current in bleu
L2 voltage (yellow)= 280Vpp

L3 is parallel tuned with 61nF
L2 is series tuned by 46nF

coils where not perfectly aligned.
output is way less then input. rather disturbing less.

Impulse still is near the V max, I should make the L2 L3 coil couple more closely at less than 23cm distance.
Also wonder if I should make the center hole of the L4 coil bigger, so it doesnt disturb the dielectric voltage aether flow.

this just feels wrong.
output is much to low

L2 L3 distance is much to big to setup a decent dielectric field.

 :(

close coupled L1 and L3 only measure 95pF!!!
imagine how low that will be when loose coupled...
4kV and 95pF hold: 0.76mJ of energy... 0.00076J
 :-/

I could close couple L2 and L3, close, and with more surface area, if instead of 1.5mm I use 0.75mm diameter wire. That also has a thinner pvc coating.

yes I've measured with 0.75mm wire, smaller phi coils, and already has 180pF. then in epoxy it should be a bit higher.
but... can it withstand the voltages?

did a quick test, with L2 L3 close coupled, and L4 close coupled to L1.
L4-L1------L3-L2

added 61nF to L2 and L3.
And loose coupled L3 L1 maybe 3cm

and yes that works also.
Max power at full resonance, no impulse. when tuned higher, impulse sits on V max of L2 as predicted.
but no current amplification, with impulse.  power factor low, but hej, this is a rough first test.

another thought I am having lately, is to slow the impulse way down, making it much lower in voltage and longer in duration.

the dc offset would then also be much lower.

in combination with the radiant half bride circuit, the prolonged impulse could be recombined with each next phase, doubling the energy.

So its a little trick with the timing.
the energy isnused twice over.
each phase is recycled in the next phase doubling the energy.

this would demand a rather big parallel capacitor over L1 to slow the impulse dowm, which becomes a problem, as the parallel cap not only is charged by the impulse, but also by the power supply, which is opposite polarity.

the impulse must be able to charge and discharge the parallel capacitor, so this polarity problem cant be solved by a diode.

if the diode would be as long as the mosfet pulse is, L1 would be (parallel) resonant.

I never played with that before.
It does make some sense, as I already have seen L1 have a current sine wave, so why not match the voltage?

If L2 is coupled at the right distance to L3 I can tune the starting point of the impulse to the zero volt point. Then the 2 half waves would overlap and sum to a much higher amplitude of voltage in L2, which then againnis transformed into a much higher current.

L3 would still be LMD resonant out if phase with L2, and couple back to L1

hmm interesting.
this would not even need the half bridge

If L2 and L3 are close coupled, the -V impulse is tuned to +V max of L2.
This is not constructive for the build up of current, as it turns in the wrong direction.

If L2 and L3 are completely loose coupled (not coupled) then the -V impulse is on the -V max of L2.
That position is constructive for the current.

If L2 and L3 are loose coupled, the -V impulse can be tuned to any where on the traject between -V and +V max of L2.
But the polarity is always wrong, for constructive current amplification, as we are on the wrong half of the phase.

This could be solved, by putting the L2 tuning capacitor on the source side again. that flips the L2 phase 180 degrees.
But then L3 and L1 will be out of phase. To solve this, without flipping L1 over, we could swap the L1 connections.
Making the center rim grounded, and the outside rim connected to the source.

If this is done, L2 and L3 are LMD resonant. The impulse amplifies the current of L2 and L3, and L3 feedsback into L1.

Then L2 can be tuned, to have its zero volt point, on the impulse. but now it is on the falling side, not the rising side. (L2 voltage going from positive to negative).
Current of L2 is still 90 degrees out of phase (only shifted when loaded). so at mosfet turn off, V=0 and I is max.
Same is for L3. So L3 current is in phase with L1, Max current at impulse, which is at mosfet turn off.

I've drawn out the phases. Impulse could be extended by parallel cap of L1 for max 1/4 waveform, during which current will be amplified. Still think, best is to get a fast impulse. But seeing that the capacity is so low...

Lets take a look at the resonant voltage and current again.
When voltage and current are present we have power.
When both are equal polarity, we are consuming power from outside.
Like with a 100W lamp. if it is burning energy from the power plant, we have positive voltage and positive current consuming power, to produce light and heat.

If the the current and voltage are out of phase, we are CREATING power.
This condition is present in the resonant coil. in the attached picture, the green parts are where the power is consumed from outside of the resonant coil.
The orange parts are where power is Generated, as we have both voltage and current present, and their polarity is opposing.
Between 1/2 and 3/4 phase we can add the negative voltage of the L1 impulse, to increase this power generation.

To get this impulse on that point, well, I have explained that in the previous posts.
Now that leaves us with the question, do we want a high voltage small duration impulse, and work with the abstract vague L2 L3 capacitor concept, which has low energy, although many times per second still makes a lot of energy.

What fascinates me, is that the orange parts seem bigger than the green parts. is that a visual illusion?

I learned so much from making my new resonant power video!

I will return to the radiant half bridge circuit to tune the L2 L3 coupling distance so the impulses will be placed as on the sketch below.

https://youtu.be/j6RRidjyqyM

before I return to the radiant half bridge (It has has a problem with the secondary impulses not being stored in cap) I will first try it with this setup, as it already is setup on my bench.
Will change  couple distance of L2 L3 until it is on the zero volt point of L2. L2 needs to go from positive max to negative max, lets call that the down cycle. To get this, I will need to reverse L1 (bummer) and the tuning cap of L2 should again be connected to the source, while the large DC blocking cap is on the drain.

before I flip L1 over, I will reverse connect it and see what that does. inside rim to ground, outside rim to source. Probably bad idea, as the center is now grounded... think outside need to be grounded....

green= L2 current
orange =L3 voltage
yellow=L2 voltage
purple= pulse
F=76.6kc/s
L2 and L3 both tuned with 61nf
L2 tuning cap on source.

See them ripples on L2 (yellow). need to get rid of them. Will return to a different mosfet driver to see if that helps.
L1 is reverse connected, inside rim to ground. dont like that at all. Will flip it over, so it is counter rotating compared to L3 where it is close coupled to.
L2 L3 loose coupled at around 20mm

pff done enough today. new video live stream in 2 hours. 1AM amsterdam time

and why is the green current not amplified the right direction (up) is that a measurement fault???  should check for L3 current amplification again.

I think the L2 L3 coils need to be a bit closer the impulse seems not to be at the zero point of L2.

instead of flipping L1, I will flip L3 over to get the phases right.

L1 and L2 can be coupled any way as I showed in the april 2019 radiant power video.

only L3 is out of phase by being LMD resonant.

Flipping L3 over also makes the Voltages of L2 and L3 in phase again

funny. I flipped L3 over, and tested, but then there is no phase shift of L2/L3 so I can't tune the impulse to the zero volt point.
Lets try flipping L1 over. That is easy now.

ok, I have now only flipped L1 over.
So L3 and L2 are out of phase again.
Tuned and it seems to work, current is down to 0.71A with 2x20.1V at 76.5kc/s
So that needs less input.
Still need to get the coils a bit closer, as at the L3 maximum, the impulse is not at or past the zero volt point of L2.
Glad this seems to work

yes!
it works as expected. Not perfectly tuned yet, but impulse is at the current maximum/voltage minimum now, and the power supply is even less then before. 0,54A at 2x20.1V dc input.
F=77.4kc/s   tuning caps still both 61nF  and only L1 is flipped over.
green=L2 current
yellow =L2 voltage
purple is L1 pulse (into mosfets)
orange is L3 voltage
bleu (rigol) is L3 current

Now need to fine tune it so the maximum L3 current is when the L2 impulse is on the zero volt of L2/L3
Great that this works!!!
And... this might be just a prelude to using the half bridge circuit, which might work better (or worse)

coil distance between L2 L3 is now around 17mm

definitely need more testing but it starts to look interesting.

I tuned the impulse to the current maximum.

the L2 current dipped at the moment of the impulse.
at first I thought that it was bad,
but maybe not. As L3 shows a rather larger amplified current. really really interesting.

I videod the test, but need to write the results down, and compare to the l2 cap on drain side setting.