I took the diodes out, and checked them again,
I was a little confused, but they are 3 pin diodes, 2 channels, and only one channel shorts out (took the hit). So I can still use one half of the diode, as long as I cut the other leg off.
But they won't be used in this circuit, maybe for something else in the future. I'll just cut the bad leg off

I probabl shorted out the resonant cap, as I usually do when I work on the circuit, for safety. The diodes then short the signal to ground bypassing L1. This explains the high current.

I replaced the diodes, with 4 mur1660CT (2 in series for 1200V) and tested. It works,
I got 550nS -828V impulses at 50.19kHz
costing me only 0.31A 14,5V at the DC input.  (4.5W)

with the circuit idle (only fan is running and buck  converter): 0.15A
so 0.15A @ 14,5V=2.2Watt to produce these impulses. very impressive.

I dropped the frequency down to 41kHz, then for the same power, I got -1100V impulses.
amazing!

BUT
No series resonant L2 coil. this is strange, dont know why it isn't resonant I went up to 275kHz ans still saw no sine (tuned with 50nF).
I placed 2 mur460 diodes in series between the V+ and the large 2uF cap (in series with the L2)
this shouldn't kill the resonance... must be someting else, frequncy cant be that high. altough I use very small coil. but before it resonanted at 100kHz....

edit: Hmm, DC offset prevents diodes from opening. will need to place the diodes at V+, so C1 can connect to mosfet, and equalise the positive voltage.

SO if the L2 becomes resonant, the impedance will drop lower, and the impulse will be even faster...

Placed the 2 series MUR1660CT to V+ and everything is working again.
The diodes protected the power supply from to high positive impulses.
Right now the impulse is to fast to form a single impulse
 :(

Its hot. 40C for several days. No airco. woke up around sun rise. Coolest of the day. Had some ideas floating, and decided to work at them.

Stacked the coils, close coupled. L3 in the middle. L1 on top, with the back emf side facing L3. L2 is facing L3 both with their resonant sides.

I used 1.63A 15.1V  DC  the powersupply acted up(unused channel giving out reading) when I grounded L3, so I removed the ground from L3 and placed it on L1 ground (V- was already grounded). Later on when I tuned L3 the power supply acted up again (I have seen this before, its not broken, seems to be from ground fluctuations).

L2 is tuned with 50nF (at L1 side on circuit)
L3 first is untuned. only loaded with a 28W halogen 230V lamp that lights up (no full brightness)

newfile 1 and 2(zoomed) show the 125nano second (!) -540V impulse. (10:1 voltage, probed at resonant inside rim L2)

newfile 3 shows L3=6nF on the blue second channel (10:1 voltage probed at resonant inside rim L3)

Very PROUD of achieving this fast impulse.
And something I hoped for, also showed up, a very fast ringing after the impulse.
It needs more calibrations, but its very nice to predict something and see it show up.
L3 still needs proper tuning...
But that for later. Sun is rising.

 in one nanosecond light travels about 0.3 meters or about 0.98 feet per nanosecond.

so during the 125nS  -540V impulse, light travels 35meter or 122.5‬feet

 :shocked:

newfile 1, two posts below, shows the impulse going off screen, so it wasn't - 540V more like - 1000V

Tuning L3 with a parallel cap. might be wrong.
Parallel resonance draws high currents due to the high impedance.
this is not ok.

So I will keep L3 loaded, but untuned.

L3 in the middle is coupled to the magnetic field of L1 and the resonant voltage of L2 on the other side.

During the impulse, L3 experiences a strong change in voltage on both sides.
This mighy be compared with a changing position of the Bloch wall.
Nut sure. need more testing.

but much to hot. 40C
cold feet helps

Until now I always made l3 parallel resonant.
the only way this works is without a extra load, like in the chair I made for health benefits.

It makes much more sense to tune L3 series resonant, with a capacitor between the coil and ground, like tesla showed in hia patents.

parallel resonance only creates a power draw from L2. It makes it a receptacle. but not a "giver"

And lets see what is possible with L3 not being resonant at all (but with a capacitor in series to ground.

All kinds of strange phenomena are happening, when I turn it on...
only use 1 channel of my 2 channel power supply, both channels can give 32V 5A
the unused channel shows 45V :shocked:

The square wave generator resets.
 :shocked:
The impulse is completely gone, absorbed into the series resonant sine. it only shows up as a ripple riding on the sine

Lamp over parallel resonant (yes series didnt work out) goes very bright, but at the same time amps go way up also.

I took a small break from it all, and now this happens, need to read back and get the right setup again. 

or... something like that...

or... produce some video's to clear my mind, of all that I have learned. get a little more distance.
play with some magnets, thats always fun

I changed the buck converter that limited my lowest voltage to 13.5V for a buck boost converter. now I can go as low as 5V and still provide the gate driver/fan with 12V.

much better

my square wave doesn't reset anymore, could have been bad powersupply contact.

the first unused channel of the dual power supply still produces voltage out of the blue. I measured it with a multimeter and its really there, but low amparage. voltage quickly drops by the meter.
maybe a cap is charged up from a rectifier connected to a mass, that swimgs (resonates) from the impulse waves. It only happens at one frequency around 65kHz.
for now I just ignore it. funny as it is.

I will short the unused power supply channel out, so the caps of that channel wont over charge(i saw 45V for a 30v channel).

I'll keep the setting at zero volts naturally.

I'll also need to check metal object im the surrounding space for polarisation, it will be probably a lot more then expected...
could even try to rectify(fast diodes plus cap) it and light a LED.

in this setup, the ultra fast impulse (less than 200nS -900V) is completely gone. only left is a ripple, on the series resonant L2.
L2 in this setup shows the greatest voltage rise, but at the same time this is also the setup with the greatest current draw.

DC: 1,88A at 13.0V  L2 is probed (10:1) on the inside at the resonant side, which is facing L1

L1 is switched on the top side, that is not facing L2. here is the impulse created (inductive spike).

This geometry makes a big difference. If the resonant sine is not facing L1, it is less powerfull, and also the current draw is less.
The side of L1 that is swithced also matters, when it is facing resonant L2 is is worse. I need to test all variants. But this one stood out, as the impulse is completely absorbed, and nly shows up as a ripple. In the end, I dont think this is the usefull setup.
We need the impulse. In this setup, the impulse is absorbed into the resonant L2.

I also did another test (no data) where I impulsed the coil, and probed a piece of metal half meter away. as expected the impulse showed up on the metal, as a 40V impulse, with a fast ring (plus and minus).

EDIT: I tried to replicate the test to see the result for all the different geometries. I noticed, a differnt result, and all the variations, didn't have variable results.
I conclude, I did this first test with opposing L1 and L2

a plate with a series capacitor to ground, like im Tesla's radiant patents,
should capture the impulse from the L2 coil.

this could be a good indicator of longitudinal power

it should be able to power a small load/lamp

I had 2 of these copper pcb's, I sprayed one of them with transparent paint. (without tape)

It will act as a single plate capacitor, jist like Tesla's patent below.

the isolated plate will charge up (connect with dielectric lines of force) from the radiant energy (ring vortex) created by the impulsed series resonant coil.

the single plate then will charge up a series connected capacitor that is grounded.

The voltage build up in the series connected  grounded capacitor, Will act as a indicator for the longitudinal field strength.

This way I have a measuring device.
Smaller capacitor will charge faster.

This is what I will be testing today.

I am very curious what yhe negative inductive spike will do.

Will it prefer the right path,
c2 L2 into a longitudinal Aether wave
or, will it prefer the left path,
C3 D2 and charge up C4 to be re used.

another exciting day of testing...

first  test no success.
probably due to c4 being much much to large as well as c3. impulse vanished, and no dc voltage change, but lots of Ringing.


impulse insight :

the longitudinal push, needs to be quick enough, short in duration. to se the aether in motion. if its slow it will create a magnetic vortex (can also be usefull)

but the quiker the impulse (shorter duration) the higher the voltage needs to be. (to have impact energy)

therefore the coil producing the impulse needs a high enough induction.

the stronger the magnetic field,
the stronger the collapsing energy.
the stronger the impulse.

if it isn't strong enough, it can't push and will ripple

if the longitudinal wave can work into a load the impulse also wont ripple as the tranfer of longitudinal energy will be recieved into a "drain" the pressure can work into the load

its again the inverse logic of counter space

make c4 smaller can be done, but I use more stuff for switching. like a 12v fan powered from a buck boost converter.

I should place that stuff (with latge caps) before the diode (directly to V+)
and after the diode, a much smaller cap, and see if that works (without all the oscillations).
@@@@@@@@@@@@@@@@@@
on another topic, I again looked at coupling L1 and L2 (no L3). all kinds of variations, still, one and the same result:
reduced current draw.
I fail to fully understand this.

and If L3 is put in the middle (close coupled) with a 28W lamp in parallel (no cap) it light up, with pretty good  efficiency (if tuned) thats also so weird.

I wanna explore this more. and simce l3 isn't resonant, also play with a distanced L3 coil (now used for L1).

then lower the frequency by making l2 caps bigger, and push more current and voltage through L1 to create a stronger impulse

Slow the impulse down if its to fast with a cap over L1...

Keep playing with these concepts until ita fully clear whats going on.

Hi if you want a higher pulse voltage across the mosfet why not cascade them to build up a high voltage pulse.
It is a very common practice.
Regards GW

Quote from GreyWolf on August 9th, 2019, 04:19 PM

Hi if you want a higher pulse voltage across the mosfet why not cascade them to build up a high voltage pulse.
It is a very common practice.
Regards GW

Yes good idea,
but I wonder how to switch it, as I use a floating(on top of changing source voltage) gate driver.

fast turn off is essential for a good inductive spike.

can you maybe share a link to a good article about cascade gate driving?

TRY THIS
https://pdfs.semanticscholar.org/55e1/b9d916cc8282e52ba3c4414aab6d640d653c.pdf

How do you post a drawing

Quote from GreyWolf on August 10th, 2019, 05:49 AM

TRY THIS
https://pdfs.semanticscholar.org/55e1/b9d916cc8282e52ba3c4414aab6d640d653c.pdf

How do you post a drawing

tnx

drawing: reply, and under it says
" attachmenta and other options"
click it
now you can attach a drawimg

Quote from GreyWolf on August 10th, 2019, 05:49 AM

https://pdfs.semanticscholar.org/55e1/b9d916cc8282e52ba3c4414aab6d640d653c.pdf

Very awesome, many thanks for sharing :thumbsup:

I have based much on my theory on the impulse. but, the experiments show it isn't correct.
The inductive spike can ripple. loosing its single voltage, spread out over several ripples of lesser voltage.

I used higher resistance coils, which give a delay to the inductive spike duration. the magnetic discharge is held back. and not a single impulse but several smaller are made. even with the L2 series resonant coil fully uncoupled.

I did a test, with equal L1 L2 L3 coils.
L2 and L3 close coupled. resonant L2 side facing L3.
L3 is not tuned, and only parallel loaded with a 21W 12V light bulb (brightly lit).
L2 is series resonant tuned with 100nF at 41.87kHz
power consumed: 1.15A 19.7V dc =22.7W

Newfile 5 shows:
 yellow L2 resonant voltage 10:1 238V peak to peak
Blue: L2 current 100mV/A 5.56A peak to peak
voltage and current are 90 degrees out of phase(series resonant). There should be no power. but there is! WHY?
The impulse is not a single high voltage discharge, but several smaller voltage ripples.

Newfile 6 shows:(same setup)
yellow L3 voltage (outside grounded) 1:1 31V peak to peak
Blue shows L3 current 100mV/A 4.9A peak to peak
Voltage and current are IN PHASE there is power, the 21W light bulb is brightly lit

Quote

So, I conclude, a single impulse with high voltage isn't needed at all. a rippled inductive spike also works.
The question remains, why?
Why is the voltage and current in L3 in phase.
Why can a series resonant coil (L2) produce power, while the voltage and current are out of phase.

What is so different with this negative inductive spike from L1 (not coupled at all) that it can do this magic?
And how do we make use of this even more?
most important: It only works when the copper mass is equal. If I use a diffenrt mass copper for L3. it does not work.

A higher inductance L1 will produce a stronger inductive spike (at the cost of more current consumption).
But I already also learned, L1 is fed with current from series resonant L2 which delays its inductive spike, until the current in L2's series resonance is reduced, and L1 is allowed to collapse its magnetic field, creating a inductive spike, that is fed back into L2.

edit:
this is not giving more out than in. The loop should somewhere be open, to allow energy in, and I still think the single negative high voltgae fast impulse is key.

edit2:
comparing newfile 5 (L2 series resonant) newfile 6 (L3 output), that are taken from the smae system, with same reference (trigger= squarewave gen).
Current in L2 and L3 is equal and in phase.
Voltage in L2 and L3 is unequal and phase shifted.
Voltage is what is influenced, dielectric field is what is shifted.

When L3 current and voltage (in phase) are zero, L2 current is also zero (in phase with L3),
 L2 voltage is the only electric field energy present. So the energy of L3 (magnetic+ voltage) is alternating with the voltage of L2

To generate a fast (short duration) high voltage impulse, a high inductance low capacitance low resistance  coil is needed.

The duration and voltage height of the of the impulse is determined by the capacitance, resistance and inductance of the coil, and the current and voltage that is put in. Along with the fastness of the opening switch, and the resistance it represents.
 
The inductance+ capacitance+ the resistance of the coil also determine its resonant frequency.  So to get a fast high voltage impulse, we need a high resonant frequency with high Q.
 Since inductance needs to be big, we need to make capacitance and resistance low. aka, thick copper wire (low resistance), and distanced windings (low capacitance)

We could even make the coil, counter wound, to get an even stronger impulse!!! It will not resonate at all, and the magnetic field strength is even stronger (at cost of higher current)

with a "counter wound coil", I mean a bifilar coil, with its series connection, from outside rim to outside rim, or inside rim to inside rim (not like tesla intended). This creates 2 counter acting magnetic fields from the 2 counter wound windings. and a low voltage difference between the windings (only between the beginning and end of the coil)

As with magnets, the opposing field (north north or south south) energy is much stronger, than the attracting (north south) energy.

I like this... I like this a lot!
lets test this one. very simple very easy... just one wire to reconnect