I have based much on my theory on the impulse. but, the experiments show it isn't correct.

The inductive spike can ripple. loosing its single voltage, spread out over several ripples of lesser voltage.

I used higher resistance coils, which give a delay to the inductive spike duration. the magnetic discharge is held back. and not a single impulse but several smaller are made. even with the L2 series resonant coil fully uncoupled.

I did a test, with equal L1 L2 L3 coils.

L2 and L3 close coupled. resonant L2 side facing L3.

L3 is not tuned, and only parallel loaded with a 21W 12V light bulb (brightly lit).

L2 is series resonant tuned with 100nF at 41.87kHz

power consumed: 1.15A 19.7V dc =22.7W

Newfile 5 shows:

yellow L2 resonant voltage 10:1 238V peak to peak

Blue: L2 current 100mV/A 5.56A peak to peak

**voltage and current are 90 degrees out of phase**(series resonant). There should be no power. but there is! WHY?

The impulse is not a single high voltage discharge, but several smaller voltage ripples.

Newfile 6 shows:(same setup)

yellow L3 voltage (outside grounded) 1:1 31V peak to peak

Blue shows L3 current 100mV/A 4.9A peak to peak

**Voltage and current are IN PHASE** there is power, the 21W light bulb is brightly lit

So, I conclude, a single impulse with high voltage isn't needed at all. a rippled inductive spike also works.

The question remains, why?

Why is the voltage and current in L3 in phase.

Why can a series resonant coil (L2) produce power, while the voltage and current are out of phase.

What is so different with this negative inductive spike from L1 (not coupled at all) that it can do this magic?

And how do we make use of this even more?

most important: It only works when the copper mass is equal. If I use a diffenrt mass copper for L3. it does not work.

A higher inductance L1 will produce a stronger inductive spike (at the cost of more current consumption).

But I already also learned, L1 is fed with current from series resonant L2 which delays its inductive spike, until the current in L2's series resonance is reduced, and L1 is allowed to collapse its magnetic field, creating a inductive spike, that is fed back into L2.

edit:

this is not giving more out than in. The loop should somewhere be open, to allow energy in, and I still think the single negative high voltgae fast impulse is key.

edit2:

comparing newfile 5 (L2 series resonant) newfile 6 (L3 output), that are taken from the smae system, with same reference (trigger= squarewave gen).

Current in L2 and L3 is equal and in phase.

Voltage in L2 and L3 is unequal and phase shifted.

Voltage is what is influenced, dielectric field is what is shifted.

When L3 current and voltage (in phase) are zero, L2 current is also zero (in phase with L3),

L2 voltage is the only electric field energy present. So the energy of L3 (magnetic+ voltage) is alternating with the voltage of L2