almost forgot to post it here.

I play with the radiant half-bridge circuit and show different wave forms, phase shifts and a triangle wave!

explanation is in the video

https://youtu.be/2fLBZu7BJkM

I played a lot with the Radiant half bridge circuit, and learned from it. The things I do with it (dual primary L1 and L2, and L3 secondary in the middle close coupled to L1) I haven't done with the original single mosfet radiant power circuit.

With the radiant power circuit, I only use 1 mosfet, for negative only impulses from L1.
Since I want to tune in the maximum current amplification in L2, it makes sense to slow down the impulse of L1 by a parallel capacitor over L1 (several hundred pF) so the current quarter wave will link up with the L2 current from the series tuning capacitor discharge into L2.

from experiments, it also has become clear, L3 needs to have a bigger capacitance than the L2 series tuning capacitance.
I had L3=61nF and L2 50nF and L3 nearly became a resonant sine, but it needed to be a bigger capacitor, or a smaller L2 capacitor.

I will remove the tuning capacitors from the radiant power circuit (april 2019 published) so I can use the capacitor tuning board. and I will add  some pF to L1.

I made 2 FFT analysis of L2 voltage (series resonant impulsed)
This is with the 2019 radiant circuit, L1 with 1.2nF parallel over it.
L3 rectified to DC and loaded with 42W lamp
L1 close coupled to L3, L3 (in the middle) loose coupled(15mm) to L2.
L1 pulsed, L2 series resonant impulsed, L3 parallel resonant

Setting of FFT1 A and B :
F=103.27kc/s
L2=21nF L3=61nF
power=0.41A (2x) 20.2V dc input. 42W lamp growing.

Settings of FFT2 A and B
F=78.57kc/s
L2= 41nF L3=61nF

I averaged the FFT (16 times) Notice the amount of harmonic content, of the combination of the impulse and the series resonant voltage sine wave.

in this link
https://teslauniverse.com/nikola-tesla/patents/us-patent-645576-system-transmission-electrical-energy

tesla patent 645576 gives very interesting information about the impedance effects that appear from the impulses.

What Tesla explains, is in line what I see in my experiments. the line of thought I first had didn't explain the effects that were seen when the impulses were of opposite polarity.

both polarity impulses had the effect of current amplification thus, could not be from resonant transformation.

something else took place. the medium was lowered in impedance by the impulses, which increased the current.

In the next year of research I will start with some tests to measure changes in impedance in the dielectric medium of distilled water.

let's take water as an analog for the Aether.
I consider Aether as a gas.

if I take my flat hand and push the water down, the water will create transverse resonant waves.

If I slap my hand fast down om the surface of the water I will "freeze" the liquid water, (not ice, but solidify) and a longitudinal wave (much faster) will travel through the water.

The ideal condition depends on the size of the hand and the speed/energy it transfers to the water.

Consider now the surface of the hand as the coil area. the speed and energy is the impulse duration and voltage.

This means the impulse for a certain coil area, needs a certain voltage and duration to "solidify" the aether.

and this generates the fast LMD wave. Which propably is responsible for the sudden change in impedance.

impedance which relates to the capacitance and inductance of the coil, which manifest around the coil.

thus the impulse is able to (or appears to) change the capacity and inductance of the coil, by changing the properties of the Aether.

this "certain" voltage and duration can only be found by experimenting.

to fast impulses will need to high voltages (and I am limited to 1700V)
to slow impulses will only make tem waves.

Luckily I already have current amplification effects, which indicate something is happening, independ of impulse polarity!

aether ~ incompressible fluid (like water), is what you meant?

Quote from coldelectric on January 1st, 2021, 09:49 AM

aether ~ incompressible fluid (like water), is what you meant?

Almost.
Aether yes,
 but like a very dense elastic gas. compression = magnetic field (current),
Tension = dielectric field (voltage)

In relation to impulses, this dense gas changes its properties.

have taken a break and distance from research. This always gives new perspectives.

the last setup I used with the radiant half-bridge circuit had L2 loose coupled to L3.
with L3 in the middle tight coupled to L1.

I think that does not make a lot of sense.

L2 is impulsed. and these impulses have effect on the neighborhood.
L2 and L3 are both resonant and tuned to the same frequency.

So close couple L2 and L3, as a single resonant field, whereby the impulses of L2 can directly influence L3.

furthermore L1 is not resonant. it is pulsed way below its resonant frequency. therefor it should be loose coupled to L3/L2.

L1 produces magnetic fields, that induce voltage in L3.

and L2 produces intense dielectric (and magnetic) fields that induce current/magnetic fields in L3.

L3 and L2 become one in their magnetic field when close coupled. thus the amplification of L2 magnetic field from the impulses, should then also be present in L3.

It all makes a lot of sense. But I might be wrong. we'll see soon enough how this works out.

the hammer energy is the impulse created by the turn off of the mosfet switch.

this turns off the supply of voltage to L1, which has build up a magnetic field.

the magnetic field lines of L1 are opened up quicly by the mosfet switch and transform at the rate of resonance of L1 into a dielectric voltage impulse.

This impulse from L1's magnetic field energy transformation is the hammers energy...

the impulse is fed into L2 which is series resonant (low impedance). the sudden voltage change of L2 by the impulse of L1, is what turns  L2 into a hammer.

L3 is the anvil on which the L2 hammer slams.

more L1 inductance = more L1 magnetic energy =stronger impulse. (but also longer duration due to lower Fres)

more voltage = more magnetic L1 energy = stronger impulse (better than high inductance)

nice work like it

Quote from evostars on January 1st, 2021, 10:16 AM

Almost.
Aether yes,
 but like a very dense elastic gas. compression = magnetic field (current),
Tension = dielectric field (voltage)

In relation to impulses, this dense gas changes its properties.

indeed, I was mistakenly thinking of Tesla quote that "whatever electricity is, it behaves like an incompressible fluid."

whereas the aether, on the other hand, I think he calls a material of "incredible tenuity", which would mesh better with a more dispersed character, as of a gas. Perhaps, the aether is somehow an empty channel, ready to direct the electric 'slug' coming thru the pipeline? In radial coordinates... Or not!

**reaches for more water imagery, takes deep breath instead lol**

My break has ended. I have had some distance from my work and from the birds eye view recieved new insights.

For example, L2 and L3 are both resonant, so they can be close coupled. L1 is not resonant so it is best to loose couple it to L3.

the faraday tubes represent the dielectric lines of force. As they move side ways they drag alomg the Aether.
the dense Aether has inertia and gains momentum. This is the magnetic field.

the faraday tubes are elastic and their tension represents voltage.

they form loops around the dragged alomg aether.

around a series resonant bifilar coil (L2) right after the voltage maximum, the faraday tubes start moving sideways, and the volume of aether is starting to be dragged along (in a new direction).

The flexible loops under tension (voltage) start to bend.

If a voltage impulse (from a inductive spike of L1) is injected at that moment in time, the tension of the faraday tube is made much larger, and thus the tube loop stiffens and is able to kick the volume of aether into a much bigger stronger motion.

This I have seen in my experiments.
But it does not explain the effects of an oppositite polarity impulse. as it ALSO amplifies the current.

So something else happens.
It's as if the faraday tubes sudden tension change, shocks the aether. Making it different.

Also from another view,
a capacitor which is impulsed could change its dielectric properties, and by changing its K (dielectric constant) appear as if it has a very different value.

these things I will test with Water.
Let the experiments commence again!
 :yoda:

As voltage is represented by the tesnion of a Faraday tube, what is the difference between polarities?
From the theory, it is said that a negative terminal is like an electron,
while a positive terminal of the faraday tube is inside the atom, the positive proton.

So the faraday tubes would have different connections on its ends. very strange and mysterious...
but good to keep in the bakc of my mind, as I am seeing differences in effects from the positive and negative impulses.
The negative impulse appears to amplify the current more. but this needs further testing.

the Radiant power 2019 circuit failed today.

then hooked up the radiant half-bridge circuit which also failed. I remembered before I took my break it broke down.

probably overloaded a diode again. Stupid thing is you cant test for reverse recovery. the diode appears working, but it wont block the impulses anymore.

Will fix it.

Have a long list of test and video that I intend to do.

Tried making a simple make shift circuit, but couldn't get a single impulse, only a lot of ringing. pfff need to get back in ti the saddle and get things going again

Since I still have several c2m 1700V SiC mosfets, I will (re) design the pcb so it has space for 2x 2 mur8100eg blocking diodes with cool body's and fans.

Since another diode has failed, I will now place the cooling fans directly on the diode cooling body's.

The mosfet body diode will also need cooling but seems to need less.

I also intend to update the BOM of the current radiant half-bridge pcb, as many people had problems finding the right caps

L2 is the impulsed primary and L3 is the secondary

L1 is the pulsed primary

I will use a coil with more windings for L3
to step up the magnetic and dielectric induction from L1 and L2 into L3.

Goal is still to have a dual primary, for simultaneously dielectric and magnetic induction into L3

I fixed the halfbridge circuit. the positive impulse blocking diode was not blocking any more.
You cant measure this with a diode meter, then it shows working.
But I see it from the signal, that starts ringing for half waves, the half wave starts on the negative voltage, so the positive voltage impulse isnt blocked.

I also placed the fans onto the cooling body's of the diodes. I pumped the impulse to 800V at 160kcps to check if they would hold, and they did. 25C max. The mosfets didn't overheat, they cool enough from the heat sink, without fan. they stayed around 20C

Many have requested an update of the BOM of the Radiant half bridge PCB, specifically the capacitors.
I also added links to the "custom attributes"> "supplier part".

You need to be logged into EasyEDA to see it apparently, so here is a direct link to the BOM on my website:
http://magstar.eu/wp-content/uploads/2021/01/BOM_gate-driver-for-half-bridge_2021-01-21.csv

https://oshwlab.com/MasterIvo/radiant-half-bridge-900
https://easyeda.com/editor#id=1fa6ba959b6844d598ef1974f6bed660

L3 is the parallel resonant secondary.
L1 is the pulsed primary.

L2 will be set aside.

I need to find the ideal distance between L1 and L3 for the best coupling. So L3 will give maximum amplitude.

I will use the larger more windings coil for L3 for step up.

L2 should be out of the way, not influencing the l1 l2  coils fields

Again... when changing distance between L1 and L3, the mutual inductance and capacitance will change, so how to get a proper ideal distance? Could I compare resonant energy in the L3 with input power?

and what about L2, it also needs to be tuned. Easiest would be to use a fixed frequency, and vary L3's parallel capacitor for tuning to the change in distance to L1.

Each time measuring Q from capcitamce and voltage, make a table and find the ideal distance...

series resonant L2 and L3 will share their magnetic field. L2 is amplified by the impulses, so should L3 be amplified.

series capacitance of L2 and parallel capcitance of L3 will need to be tuned for max current amplification.

since the fields are outside of the coils, the resonant sides of the coils should not face each other. this is in respect to the 2 layer speaker wire coils I use. where L2 and L3 couple should be the grounded side of the coils.

so the side of L2 where the impulse enters (in the middle) should be onnthe outside of the 3 coil stack

I placed the series resonant impulsed L2 on the left side and loose coupled L3(bottom) and L1 (top)

Looking at the voltages sines of L2 and L3 and the current of L1.

seeing very interesting phase shifts. need to think this over properly. very interesting to see voltage sine of L2 come in phase with the current sine if L1.

I did a very quick rough test.

placed a 1.5 liter water bottle on the impulsed series resonant bifilar pancake coil and put electrodes (silver wire) in and measured resistance.
it was 18k ohm (1.3cm).

when I put the system on, the resistance went up to 19k ohm.

I could turn it in and off and see the resistance jump up and down between 18 and 19 k ohm.

the electrodes were only 1cm submerged on top.

did several test to see loose coupling of L1 and L3, with L2 placed aside out of their fields.

not done yet.

very strange to see the phase shifts whereby the L1 current and L2 voltage become in phase, due to the phase shift of L3.

Food

spin that wheel

LOOK close
Uni polar doc attached

Quote from securesupplies on January 22nd, 2021, 11:09 PM

Food

spin that wheel

LOOK close
Uni polar doc attached

I took a look at that file, "EVO WORK " from there on its all quotes from this workbench :)
I looked into the unipolar motor in the past. seems very mysterious. might inspire someone.