ok... so we have been battling out the idea here on the forums. Its time to ask the Question.

here is basically whats in the video, ( but i would still watch it...)

https://youtu.be/72mVo5U4ad8

If I have an Air Motor, that will run at 1PSI per min (flow) , and full torque at that 1PSI

Given 1 tank through the air motor out to ATM I will get 99 min of run time... this will be our "max run time". (call it 100%)

If I split 1 high pressure (100PSI) tank in to 2 lower pressures. (50psi each)

Those 2 lower pressures will = the same amount of work as the 1 higher pressure tank ( lest say we are going to use it to power a low pressure pump anyway only 1psi was needed...)

so there for during the time where we used the transfer energy... was not "used" it was just "moved"... and during that transfer it gave us useful work. just like a wind mill. moving air from one place to a another did not change the amount of work it could do. and during the transfer we got a windmill to move and make power? same amount of air from one spot to the next.

example A.

1 Tank run

100psi consumed by the 1psi pump at the rate of 1psi per min = 99 min of run time.

we have a total of 99 min of run time. ( we lose that 1 PSI)

example B.

split the pressure in to 2 tanks with an air motor between

100psi consumed by the 1psi pump at the rate of 1psi per min in to a second tank = 49 min of run time.

we have a total of 49min of run time.

B1. we still have 50 PSI in 2 tanks now.

B2. empty the 2 tanks in to the ATM.

50psi consumed by the 1psi pump at the rate of 1psi per min = 49 min of run time.

50psi consumed by the 1psi pump at the rate of 1psi per min = 49 min of run time.

we have a total of 98 min of run time for B2

so B + B2 is 49+49+49= 147 min of run time.

example C:

split the pressure in to 2 tanks with an air motor between

100psi consumed by the 1psi pump at the rate of 1psi per min in to a second tank = 49 min of run time.

we have a total of 49min of run time.

C1. we still have 50 PSI in 2 tanks now.

C2. empty the 2 tanks in to 2 more tainks.

50psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

50psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

we have a total of 48 min of run time for C2

C3. 4 tanks now with 25PSI in to the ATM.

25psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

25psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

25psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

25psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

C3 = another 96 min or run time..

we have a total C + C2 + C3 so 49+(24x6) = 193min of run time...

example D:

we could keep doing this... however will stop at C3 for this thought experiment.

That is 193 min of run time. where as we only had 99 min of run time to start with. ( from a stranded point of view)

so with this said. where have i gone wrong?

I'm excluding a lot of things as this is a thought experiment. so for now it either is wright or wrong.

post your comments...

next we can do this with 1000PSI, and a real air motor. calculate the losses and still see that its possible to do this in the real world.

the point of this thought experiment is that the load never " consumes" the energy. in fact the load is only there to act as a resistance. but never consumes anything... next step, convert This idea to an electrical system... dose resistor "consume" the energy??? ( if its not generating heat...)

"original" ideas from here: https://www.youtube.com/watch?v=SE-AiC9yiFc

~Russ

here is basically whats in the video, ( but i would still watch it...)

https://youtu.be/72mVo5U4ad8

If I have an Air Motor, that will run at 1PSI per min (flow) , and full torque at that 1PSI

Given 1 tank through the air motor out to ATM I will get 99 min of run time... this will be our "max run time". (call it 100%)

If I split 1 high pressure (100PSI) tank in to 2 lower pressures. (50psi each)

Those 2 lower pressures will = the same amount of work as the 1 higher pressure tank ( lest say we are going to use it to power a low pressure pump anyway only 1psi was needed...)

so there for during the time where we used the transfer energy... was not "used" it was just "moved"... and during that transfer it gave us useful work. just like a wind mill. moving air from one place to a another did not change the amount of work it could do. and during the transfer we got a windmill to move and make power? same amount of air from one spot to the next.

example A.

1 Tank run

100psi consumed by the 1psi pump at the rate of 1psi per min = 99 min of run time.

we have a total of 99 min of run time. ( we lose that 1 PSI)

example B.

split the pressure in to 2 tanks with an air motor between

100psi consumed by the 1psi pump at the rate of 1psi per min in to a second tank = 49 min of run time.

we have a total of 49min of run time.

B1. we still have 50 PSI in 2 tanks now.

B2. empty the 2 tanks in to the ATM.

50psi consumed by the 1psi pump at the rate of 1psi per min = 49 min of run time.

50psi consumed by the 1psi pump at the rate of 1psi per min = 49 min of run time.

we have a total of 98 min of run time for B2

so B + B2 is 49+49+49= 147 min of run time.

example C:

split the pressure in to 2 tanks with an air motor between

100psi consumed by the 1psi pump at the rate of 1psi per min in to a second tank = 49 min of run time.

we have a total of 49min of run time.

C1. we still have 50 PSI in 2 tanks now.

C2. empty the 2 tanks in to 2 more tainks.

50psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

50psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

we have a total of 48 min of run time for C2

C3. 4 tanks now with 25PSI in to the ATM.

25psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

25psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

25psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

25psi consumed by the 1psi pump at the rate of 1psi per min in to another tank = 24 min of run time.

C3 = another 96 min or run time..

we have a total C + C2 + C3 so 49+(24x6) = 193min of run time...

example D:

we could keep doing this... however will stop at C3 for this thought experiment.

That is 193 min of run time. where as we only had 99 min of run time to start with. ( from a stranded point of view)

so with this said. where have i gone wrong?

I'm excluding a lot of things as this is a thought experiment. so for now it either is wright or wrong.

post your comments...

next we can do this with 1000PSI, and a real air motor. calculate the losses and still see that its possible to do this in the real world.

the point of this thought experiment is that the load never " consumes" the energy. in fact the load is only there to act as a resistance. but never consumes anything... next step, convert This idea to an electrical system... dose resistor "consume" the energy??? ( if its not generating heat...)

"original" ideas from here: https://www.youtube.com/watch?v=SE-AiC9yiFc

~Russ