When at resonance the imaginary part of the electrical impedance is zero. So the resistance of the water between the plates should be:

(see http://en.wikipedia.org/wiki/Electrical_conductivity for more information)

R = ρ*L/A

ρ sea water = 2×10−1 ohm*m

ρ drinking water = 2×101 to 2×103 ohm*m

ρ deionized water = 1.8×105 ohm*m

L Meyer Cell = 2.5 inch = 6.35 cm

Diameter inside = 0.5 inch = 1.27 cm → r = 0.635 cm

Diameter outside = 0.75 inch – (2*0.03 inch) = 0.69 inch = 1.7526 cm → r = 0.8763 cm

Gap = 0.095 inch = 0.2413 cm

Width Inside Meyer Cell = 2*π*r = 2* π * 0.635 = 3.98982 cm

Width Outside Meyer Cell = 2*π*r = π * 0.8763 = 5.50596 cm

A inside = 3.98982 * 6.35 = 25.34 cm2

A outside = 5.50596 * 6.35 = 34.96 cm2

So for drinking water the R should be between:

Rmin = 2×101 * 0.002413 / 0.002534 = 19 ohm

Rmax = 2×103 * 0.002413 / 0.003496 = 1380 ohm

Problem is still that since we use tubes what width do we use, inside or outside? Any comments/ideas?

(see http://en.wikipedia.org/wiki/Electrical_conductivity for more information)

R = ρ*L/A

ρ sea water = 2×10−1 ohm*m

ρ drinking water = 2×101 to 2×103 ohm*m

ρ deionized water = 1.8×105 ohm*m

L Meyer Cell = 2.5 inch = 6.35 cm

Diameter inside = 0.5 inch = 1.27 cm → r = 0.635 cm

Diameter outside = 0.75 inch – (2*0.03 inch) = 0.69 inch = 1.7526 cm → r = 0.8763 cm

Gap = 0.095 inch = 0.2413 cm

Width Inside Meyer Cell = 2*π*r = 2* π * 0.635 = 3.98982 cm

Width Outside Meyer Cell = 2*π*r = π * 0.8763 = 5.50596 cm

A inside = 3.98982 * 6.35 = 25.34 cm2

A outside = 5.50596 * 6.35 = 34.96 cm2

So for drinking water the R should be between:

Rmin = 2×101 * 0.002413 / 0.002534 = 19 ohm

Rmax = 2×103 * 0.002413 / 0.003496 = 1380 ohm

Problem is still that since we use tubes what width do we use, inside or outside? Any comments/ideas?