When at resonance the imaginary part of the electrical impedance is zero. So the resistance of the water between the plates should be:
(see http://en.wikipedia.org/wiki/Electrical_conductivity for more information)
R = ρ*L/A
ρ sea water = 2×10−1 ohm*m
ρ drinking water = 2×101 to 2×103 ohm*m
ρ deionized water = 1.8×105 ohm*m
L Meyer Cell = 2.5 inch = 6.35 cm
Diameter inside = 0.5 inch = 1.27 cm → r = 0.635 cm
Diameter outside = 0.75 inch – (2*0.03 inch) = 0.69 inch = 1.7526 cm → r = 0.8763 cm
Gap = 0.095 inch = 0.2413 cm
Width Inside Meyer Cell = 2*π*r = 2* π * 0.635 = 3.98982 cm
Width Outside Meyer Cell = 2*π*r = π * 0.8763 = 5.50596 cm
A inside = 3.98982 * 6.35 = 25.34 cm2
A outside = 5.50596 * 6.35 = 34.96 cm2
So for drinking water the R should be between:
Rmin = 2×101 * 0.002413 / 0.002534 = 19 ohm
Rmax = 2×103 * 0.002413 / 0.003496 = 1380 ohm
Problem is still that since we use tubes what width do we use, inside or outside? Any comments/ideas?
(see http://en.wikipedia.org/wiki/Electrical_conductivity for more information)
R = ρ*L/A
ρ sea water = 2×10−1 ohm*m
ρ drinking water = 2×101 to 2×103 ohm*m
ρ deionized water = 1.8×105 ohm*m
L Meyer Cell = 2.5 inch = 6.35 cm
Diameter inside = 0.5 inch = 1.27 cm → r = 0.635 cm
Diameter outside = 0.75 inch – (2*0.03 inch) = 0.69 inch = 1.7526 cm → r = 0.8763 cm
Gap = 0.095 inch = 0.2413 cm
Width Inside Meyer Cell = 2*π*r = 2* π * 0.635 = 3.98982 cm
Width Outside Meyer Cell = 2*π*r = π * 0.8763 = 5.50596 cm
A inside = 3.98982 * 6.35 = 25.34 cm2
A outside = 5.50596 * 6.35 = 34.96 cm2
So for drinking water the R should be between:
Rmin = 2×101 * 0.002413 / 0.002534 = 19 ohm
Rmax = 2×103 * 0.002413 / 0.003496 = 1380 ohm
Problem is still that since we use tubes what width do we use, inside or outside? Any comments/ideas?