Hello, A nice little circuit to play with here.
No chokes, just a transformer with a 20kv output, an high voltage resistor, high voltage diode and a small fuel cell.
No chokes or complications. The trick to this circuit is the phase angle between R1 and C1.
AC is passed through R1 at a small current, C1 will charge but only if there is no phase relationship R1 and C1. That is achieved by always having a 10x higher resistance than the dielectric property of the cell in PF.
Current will then lag voltage into both R1 and C1 simutaneously but don't let the current pass through the water!!!!!
Have a nice day.

Hey Nav, long time, good to see you :)
So all voltage no current to the water fuel cell then?
Most interesting :thumbsup:

Quote from Lynx on December 7th, 2021, 08:14 AM

Hey Nav, long time, good to see you :)
So all voltage no current to the water fuel cell then?
Most interesting :thumbsup:

Hi Lynx, nice to see you again.
I'm currently atomizing resistors at an alarming rate. I'm going to need to move the resistance towards a spark gap but spark gaps have varying degrees of resistance which is impossible to measure. I'm working with an adjustable ganged capacitor which varies from 0-195PF in water and 0-25PF in air. With a dielectric constant of 2, it's about 0-40PF. If I adjust the cap I can find where the resistor and cap have zero phase angle to each other. When this happens it allows the current to lag voltage by 90 degrees into the resistor and cap simultaneously. This is what causes problems in Meyer technology. If the voltage phase hits the cap before the resistor, you get current through the water. If it hits the resistor first then the cap won't charge and just sits. The trick is to have no phase angle between the resistor and cap, when this happens current goes through the resistor and the cap charges at the rate of current in the resistor. It's almost the same as cancelling the inductive and capacitive reactance out on a transmitter circuit.

Season Greeting nice post have a Happy New Year

Hey nav. Have you tried two partnered bucking coils as L2. One wired CCW one CW with no Centre tap. ( winding just reverses direction at the mid point)

Quote from Evengravy on December 15th, 2021, 05:03 AM

Hey nav. Have you tried two partnered bucking coils as L2. One wired CCW one CW with no Centre tap. ( winding just reverses direction at the mid point)

Hi. I think just about every type of bucking coil arrangement has been tried including switchmode power supplies where you isolate two switchmode power supplies using the positive from one supply and the negative from another supply which is what you are alluding to. The trouble is, you can't isolate anything while ever you use domestic power because nothing can be isolated when it uses the same common neutral and hot wires. Thats why Stan drives a generator with a motor and creates an isolated circuit which is free from outside biased electricity.
For example, in a simple analogy, if you use two generators to create two seperate sources of power what do you have? You have two ac sources which are not related to each other and if you rectified both voltages and tried them on a cell what would happen? The answer is nothing. It would be the same idea as driving two PWD's with two different batteries and doing the same experiment. No voltage can be measured across the cell. Why? Even though you could use resistance to get current flowing in both circuits, each circuit recognises only its own phase relationship to the load, they don't recognise each others phase relationship unless they are part of the same generator phase.
So why was Stan using a generator instead of domestic electricity? Because domestic electricity is biased to use current and you cannot possibly impedance match the source to the load in this way, the impedance is very low. If we truely matched the power companies impedance through our loads then we would consume far less current. The truth of the matter is the power companies force us to create standing waves in their system but the standing waves are created within the load itself.
Stan can take a generator, work out the operating impedance and match that through the conductors and the load itself. If you use a resistor at this impedance then the circuit will operate with no standing waves and the push pull effect through the generator and load will be an exact match. Once you have resonance in this way. you can start to play with capacitance and inductance using the same impedance knowing that because you are no longer connected to a domestic supply, you are not being forced to create standing waves in those componants in reference to the power company.
You see, it's all about reference. It all references back to the power company if you let it. Don't let it.

So, we have to go to the drawing board and learn the basics of electricity. Lets look at phase reference and ask a few questions. The first question is this: Can I take a dometic power supply of 60hz, rectify it with a diode, connect the positive to a capacitor and then reference the negative to a battery? No, the battery is not oscillating at 60hz for a start and even if it was, it has no reference to the domestic supply.
Second question, can I somehow isolate a domestic supply so that the load has no reference back to the power company. The answer is no. Even a 1:1 isolation transformer in audio equipment has reference back to the power company, everything does.
A reference back to the power company means current will flow through the water of a cell no matter what you do even if you use a spark gap.
So what system would allow one plate of a cell to be positive and the other to be negative while having no reference in terms of current back to the power company source? Always remembering of course that current is simply flowing from the hot wire to the neutral of a power source. Well if you have a diode in the circuit, it allows current to flow the very same way. That won't work. Two diodes in opposite directions stops positive charge from reaching a capacitor at all so that won't work. It all boils down to reference back to the power company and hiding that reference. How do you hide it? The only way is kinetic energy. Driving a generator with a motor is the only way you can isolate domestic energy from the cell.
Once you do that, you can build your system around your own source of power and not that of the power company. You can resonate coils, capacitors and resistors in accordance to the source of power with absolutely no reference back to the power company. You can also do it with batteries.
If you can control the impedance of a circuit from source to load, you can also create an high impedance to the flow of current within that circuit because their is a differential. Domestic supplies will not allow this because no matter how many componants you place in the circuitry, the load will ALWAYS reference the very low impedance of the source.
With this in mind, you can build a system using your own source of power with a controlled impedance, within that system you can create higher or lower impedance in reference to the source and you can spend energy using differential current and voltage within it.
The cell, is simply an apparatus that presents an high impedance to the flow of current compared to the controlled source impedance and NOT power company low impedance.

If the power company has zero impedance, it doesn't matter how many resistors and other componants you place in your circuitry to create your own impedance platform, all of them are in reference to zero impedance including the load itself.
It really is as simple as that!
The source is the only reference you have when you create high impedance to the flow of current, you can't create high impedance in reference to other componants in the circuit because the source controls those too. Neutral in power companies is referenced to ground and very low impedance. If you create a indepedant source of power that is only referenced to itself and that source is 500ohms, then you can create a lower impedance in reference to 500ohms of 100ohms which is a true reference of 400ohms differential.
Power companies won't allow you to do that because the neutral is zero ohms. You simply cannot reference 100ohms to zero ohms, you will always have 100ohms no matter what you do.

So now we create a new reality in electrical terms. Instead of having a source of zero ohms we can have a source of 500ohms. It allows us to create differentials below the source impedance and differentials higher than the source impedance at the same time. We couldn't do that before.
If we create a source of 500ohms, any componant we use below 500ohms will be a true relection of the effect on the source.
This is a different world. An high impedance to the flow of current within this world is no longer an high impedance to the flow of current against zero ohms but an high impedance to the flow of current at 500ohms. What does this mean? It means that voltage can build on a cell without current because you didn't kill the voltage with zero ohms.
I'll explain the best I can. If you have voltage and current inside a transformer operating at a certain frequency, the system is always operating against a source impedance of zero. If you introduce an high impedance to the flow of current, the impedance operates against the source impedance of zero then the voltage field is static. It cannot leave the transformer.
The transformer will only ever be referenced to zero ohms no matter what you do. However, if you create a power source of 500ohms and you operate the transformer at 500ohms, it can never ever reference zero ohms, it can only ever reference 500ohms. If you then create an higher impedance in the transformer than the source, lets say 250ohms higher, you will create an high impedance to the flow of current but you won't kill the voltage because the voltage will remain at 500ohms not at zero like domestic supply. So you create a differential where current sees an high impedance but voltage see's a lower impedance because you haven't allowed it to be static which is exactly what domestic power supplies do, once you introduce high impedance to domestic supplies, it kills the voltage at zero impedance.

So if we transfer this knowledge to Stans world what do we see. We see that he introduces a source of power that is of a certain impedance. Lets say Stans generator runs at 220ohms. Current and voltage run through Stans equipment at 220ohms from source to load in normal electrical conditions. If you run a resistor at 220ohms in stans system then the resistor is resonant and it will consume power at that equation. If you run a resistor at 300ohms then in reality that resistor is actually 80ohms and it creates a standing wave and will consume more power. If you run a resistor of 150ohms then that resistor is actually 70ohms and will consume more power with a standing wave. This is ac, it works both ways. How does Stan get voltage into the cell? He creates an high impedance to the flow of current in the circuit of perhaps 1000ohms which is five times more resistive than his normal resonant condition of 220ohms. Normally, such a circuit would kill the voltage because we'd reach zero ohms against a domestic supply but Stan's source is 220ohms from the generator not zero. When he kills the current with an high impedance the voltage continues to resonate at 220ohms not zero and if you have a capacitor tuned to 220ohms impedance the voltage will build at the systems natural impedance. The diode has a bias on the voltage and it doubles the frequency but as long as that frequency is at 220ohms it doesn't matter in the slightest. If you don't kill the voltage with zero impedance, your cell will work. Using a 220ohm resistor across domestic power supplies will not work because that resistor is in reference to zero impedance from the power company and any high impedance you create in the circuit isn't in reference to that 220ohms you soldered in the circuit, it's in reference to the power company. No amount of componants will ever give you 220ohms source impedance, only the generator can do that.

Since the days of Tesla, power companies have known that if they send power to consumers at perhaps 220ohms, they'd be on a hiding to nothing and would lose money so they won't allow it. Clever people would impedance match their system and send the power back in a resonant condition. To avoid this they put their power to ground so you can't impedance match their source. No amount of componants can impedance match their source and they know it. You cannot emulate zero impedance.
Stan simply impedance matched his own source, used the frequency of the source to create an high impedance to the flow of current and bled the voltage off at source impedance. Stan cannot consume current in his system because it would be consumed at ohms law the same as the power company, maybe a little less at resonance of the system but it will consume power. What he can do though is seperate the current from the voltage, collect the voltage and present an high impedance to the flow of current which matches the systems impedance.

Thank you nav I re read this again and again

it makes sense also why  he moved to round bobbin
if we  look at your drawing.  Very Hard work to keep it simple.

Dan

I put this here as it is Relevant

Quote from warj1990 on May 26th, 2022, 04:47 PM

Figured I would post an update in this area, maybe shed some light on resistive wire.

This is for the "Tri-coil Configuration" designed for the injectors.

I have seen reference to different AWG wire for the secondary and chokes (some 34, some 40, some 32, some 36AWG)...I don't think it matters much overall.

Lets start by clarifying this design is basically one large transformer.  Primary, Secondary, and Bifilar chokes all on one core.

Each choke coil is bifilar wound and 11,600 ohm value per cavity.   14 sections (cavities) on the coil total.
11,600 * 14 = 162,400 ohms. (Bifilar chokes)

Stan mentioned the target was 5,000 volts on the secondary.   (drawings outside the tech. brief)

5,000 volts / 162,400 ohms = 0.031 amps.

Add in the secondary copper resistance and water resistance and the total amps are reduced even more.

The resistive wire is designed to prevent amp "influx" and "arcing" across the injector gap (0.010") while searching for the resonance frequency.


Still no coated resistive wire but without it you will need something like 400,000 FT of copper (34awg) to be equal in resistance value.

Thinking about just splitting the secondary coil and throwing in two 50k ohm, 50 watt resistors to test.