"The power generator can be considered as a voltage source with an electromotive force and a source impedance which in the case of the utility supply very small. The power factors are defined for loads not for power sources"
a load with a PF of 0 and a
so, lets say you isolate the Source from the Load. so that you have Absolute 0 power in the circuit. seen by the source.. but you have real current flowing through the load. and the Net power is more than 0.
this gets confusing because there are 2 things here to look at. the source from the power plant and the local source to the local load.
we get docked by the power plants to have a bad PF ( industrial places do) . so we kinda want the good PF on one side of the circuit. we want the power to go back to the source and show up as a Absolute 0 power. but in the load we want to see this reactive power.
Take a transformer, consider the primary a load for the power company, and consider the secondary a source for your local load.
now, If the local load and the local source are working together to achieve a power factor = 0 then the source sees no load.
and that reflects back to the primary as a "no load" Yet the power company still sees a PF = 1 but with virtually no load.
so now both sides are happy.
now the real discussion. if you have purely reactive circuit. your doing nothing but moving ENERGY around... no POWER is available... only ENERGY. ( in the forum of a magnetic field or a dielectric field )
yes if i place a resistor in the line where the ENERGY is going back and forth... will it not get hot? Ihis is the result of " WATTLESS POWER"
something to think about...
This goes back to the question of dose the load consume the ENERGY?