This is probably just faulty logic on my part, but has anyone tried this simple experiment? (sorry I have virtually no test equipment at the moment to check this myself)
A capacitor C1 discharges into a series of three capacitors, Co, Cm and Co:

The outer caps Co are large, but the middle one Cm is tiny, maybe just a spark-gap.
Now when Cm is shorted by the closed switch, the total series capacitance Ctotal is (1/Co + 1/Co)-1= Co/2. This is still a large capacitance, so C1 can discharge into the series, inducing charges on the two outer Co capacitors.
But when the switch is opened, the middle Cm becomes part of the series, and since it is so small, it makes the total series capacitance Ctotal almost zero. Therefore, it loses its ability to hold charge, and so the charge should migrate back to the source capacitor C1.
I can't see why this process wouldn't be repeatable, if the switch opens and closes repeatedly, would it cause a current to oscillate in the loop?
A capacitor C1 discharges into a series of three capacitors, Co, Cm and Co:
The outer caps Co are large, but the middle one Cm is tiny, maybe just a spark-gap.
Now when Cm is shorted by the closed switch, the total series capacitance Ctotal is (1/Co + 1/Co)-1= Co/2. This is still a large capacitance, so C1 can discharge into the series, inducing charges on the two outer Co capacitors.
But when the switch is opened, the middle Cm becomes part of the series, and since it is so small, it makes the total series capacitance Ctotal almost zero. Therefore, it loses its ability to hold charge, and so the charge should migrate back to the source capacitor C1.
I can't see why this process wouldn't be repeatable, if the switch opens and closes repeatedly, would it cause a current to oscillate in the loop?