its your turn to answer some questions...
q1) pressure increase is zero....yep zero your reservoir is open you would have to have the flow go through two check valves to hold a increase in pressure.. and what distance are the check valves apart and the diameter of the pipe.
.Did you mean what is the force on the valve?? force being different to pressure
Your Capacitor is more like a reservoir.
The flow of water being shut off suddenly would return a shock wave (wave (frequency) hold that thought for later answers to questions below) to the reservoir and a small resonance would be created, In a gravity fed system mostly created by gravity/pressure (head pressure) and any incline in pipe over length (gravitational acceleration). Using a pump under the pressures you're talking about this frequency would have a high peak but quickly dissipate to the open system through the pump (probably damaging the pump in process), unless pipeline is enclosed between two check valves....as a plumber I'd have fitted my double check valve to maintain this pressure if connected to a open gravity fed system to stop my taps splurging when opened again as air would want to re enter.
Q3) Is all about Impedance and the charge. When you suddenly shut off the moving current the impedance changes because the frequency changes.
The frequency soars for that instance of time and affects the Reactance in our (Z) impedance calculation. The higher frequency will lower impedance and the energy has no (imaginary) resistance Reactance almost a dead short effect.
I surmise The charge attracts more like charges free electrons (that are non localised in the air) get drawn into the circuit (because the circuit has a direction of flow and the field holds non localised electrons from wandering off) with more electrons amassed into a area held by the field allows for more quantized energy movements to take place within that field...meaning more energy in the circuit. which we capture back into out capacitor or battery.
If you opened the switch at your very peaks of your sine wave you should not see the frequency change and no spikes but being that accurate is beyond me.
Q4) A Capacitive charged system has no real resistance, therefore it generates no heat. A capacitor cannot dissipate power (unless its a poor capacitor)
So when our capacitive circuit goes into a extreme high frequency, (breaking a switch/reed) the reactance value changes and the impedance changes leading to little power dissipating from within the circuit (because little to non is created), the heat in the circuit (from real resistance (inductors and wires) heats the atoms in the circuit) this is drawn out and manifests in the spark which is external to the circuit (this is were closed system meets open) so heat leaves the circuit that way. Remember a hotter body dissipates more heat than same body at a lower hot temperature (i.e. the hotter something is the heat dissipates quicker). A analogy for the heat in a spark is lightning. Lightning heats the air because the air becomes a real resistor (not a imaginary resistor like reactance) as the energy flows in a current through the air the air is a good conductor that dissipates the heat better than the wire (because of convection) so more heat is lost through the air.
Unlike a normal electrical conductor, the resistance (and voltage drop) across an unconfined plasma channel decreases with increasing current flow, a property called negative resistance.
For the pressure shutting off the valve it seems like the amp build up and reversal. From observation an opposing force current can result in reversal or negative amps.
One arrangement I tried to charge a battery and strange it was negative volts after a little bit... . Did not try it again just yet need that battery.
I can only guess the reason for the spike on the other side, if the spiked voltage has current we can test for current gain from possibly a magnetic field or other induced force.
q5) I am coming to realize that it matters not what condition the electron holds (wave or particle) because in both cases we can still be assured that the electron can be transferred to a new position and from atom to atom.
Hi All, No further replies....did I send you all to sleep...if not please re read above answers as I have tried to explain myself better and have modified posts.
hummm... it is to my understanding that there is a massive pressure increase. why? because there is no compresibility.. so the pipe will blow if its to high. do to what? force...
however they don't calculate "force" they calculate pressure.. pressure = force in this thinking... i think...
@Russ reply #10pressure is not force back to my early plumbing days....we think of them as the same but they can be the same. P=force/area
it explains it well here click here for explanation
I think your thinking your pump is going to stop the force, the force needed to blow the pipe has to push against something to exert force, which is what you explain as the pressure, the pressure on a area exerts the force. but what you drawed was not plumbing.
You drawed a tank (sealed) that was having the water extracted by a pump. The act of doing this would pull a vacuum in the tank because no air is getting in. So yes the pump would create a pressurised side on one side and a negative pressure on the other. To get anywhere near your pressure you would need to have added a check valve, but you didn't state that. So with the absence of the check valve, the sudden closure of a valve on the pressurized side would only have really sent a shock wave back to the negative pressure side and it would have been absorbed...hence I said no Extra pressure. but you would have had a force in the opposite direction.
In the examples you show with water hammer in the videos they have a flow and return pipe (a loop) but thats not needed as long as some part of the pipe work has a check valve after the reservoir of the source water.
The check valve is very important to give the force a datum point to exert force from. The force is measured by a pressure in the scale you wish to choose which needs a area for the math to get the pressure.
Hope this helps
so the question is. if there was a pipe of the same ID next to the valve and it was open at the same time the other was closed... this higher "pressure" would force the water up the pipe. but... with out pressure... there would be no water going up the pipe.