Dear members, this is my first post here on Open-Source-Energy.

My question is: Can the linear electric field inside a parallel-plate capacitor be used to continuously push electrons around a circuit?

Basically, a wire runs down through the middle of the plates, parallel to the field lines. (Fig 1)
Now the plates themselves are not connected to the circuit; they should not discharge. Only the field lines interacts with the wire segment between the plates.
Now in my simplistic view, the electric field should push electrons along the wire segment towards the + plate.
Once the electrons bunch up near the + plate, what happens then? All these electrons are trying to repel each other, but are still attracted to the + plate. (Fig 2 & 3) 
Now if the wire segment were opened between the plates, the situation should be as in Fig 4: two reversely charged capacitors  (each capacitor is formed by one of the charged plates and the charges bunching up on the wire nearest the plate). If the switch in Fig 4 were closed (representing the light bulb load), would the connected plates discharge themselves through the load?
If so, you would be right back to the original situation, and the process could repeat. (once you reestablish the wire between the plates.

it is a single charge gun, you have only one shot until the forces become equalize then you have to recharge again

Quote from Ris on December 20th, 2016, 11:59 AM

it is a single charge gun, you have only one shot

...a gun, hey?  :D   but only one shot?  :-/ hmmm

Sorry for my flippancy, it was too early in the morning.

If, as you say, the situation in fig 4 is like a one-shot discharge, wouldn't that bring the system right back to its original state?
Because the original charge separation actually cost us nothing, in my view; it was provided for free by the perpetual dipole of the plates.

If we can discharge the inner plates of fig. 4 through the load, we have achieved a tiny bit of free energy, and would return the circuit to it's original state. There would be a bit of switching cost to make and break the wire segment between the plates (is it even necessary?)

I heard Tom Bearden say in one of his videos (https://www.youtube.com/watch?v=eNU3MLqyzPk&t=480s ) that a dipole is an infinite source of power, if the "source dipole" isn't "killed".

Tom routinely mentions the dipole, but he never specifically states what kind of dipole--electric or magnetic.  So an interesting thought experiment might be to look at your original post magnetically and just see if anything obvious pokes out.

I'm still thinking about your scenario Leo, which is also an interesting thought experiment.  What we can be pretty certain of is that nature will try to maintain equilibrium if at all possible.  What I'm looking for is anything that might become parametric, which means the system would become unstable and oscillate out of control.  That condition is where you have the opportunity to capture excess energy.

This circuit is so simplistic that I thought it must have been one of the well-known classic perpetual-motion machine fallacies, but so far I haven't seen anything similar on line.

It should be easy to rig it up for real and check what actually happens, but I don't have a sensitive enough multimeter.  I think I would need something with an extremely high input impedance.

As of this moment, would you believe, I actually don't know how one would measure the electric field strength at any point in space. Must do some quick revision of Electronics 1.01 ! 

Quote from Ris on December 20th, 2016, 11:59 AM

it is a single charge gun, you have only one shot until the forces become equalize then you have to recharge again

Yeah, it's much like the "cogging problem" with magnet motors. The electrons will have to overcome the repulsion of the '-' side of the capacitor as they go into the capacitor, then they'll be repulsed by the '-' plate toward the '+' plate. Net effect: 0

The same thing happens on the '+' plate in reverse... the electrons are attracted toward the '+' plate, but they must then overcome that attraction in order to get past the '+' plate and out to the circuit. Net effect: 0

Now, that's not to say that it can't be done... look at how linear particle accelerators work... that's essentially what you have here. But you have to pulse it with precise timing... the contraption has a specific resonance, and you have to get the AC voltage you feed to it exactly at that resonance. It can produce extremely high voltages. Energies up to 50 GeV.

I was really trying to understand whether shielding one side of a loop in an electric field will cause circulation to occur:

First, a little background... a voltage gradient causes a local decrease in QVZPE field radiation pressure. An electron can only receive energy from or emit energy to the Quantum Vacuum Zero Point Energy field, usually in the form of virtual photons. All point charges are "surrounded" by virtual photons, causing the point charge to accelerate separates the point charge and the virtual photons, which kicks the virtual photons on-shell, allowing them to have effects upon real-world matter... that's how magnetism manifests, and why magnetism (mediated by virtual photons) has the effect upon real-world matter that it has.

Thus, if you were able to build shielding to such exacting specifications that it operated as a Casimir cavity, then yes, you'd see a current flow in the wire... except it's taking its energy from the voltage gradient in the capacitor plates, so you'd still see current being consumed in the capacitor. It's a conversion from electric to magnetic (virtual photons) to electric... a DC transformer, if you will.

{Edited to correct a hole in my understanding.}

may be useful
http://energythic.com/view.php?node=208
http://energythic.com/view.php?node=209

Quote from Cycle on January 4th, 2017, 04:37 PM

First, a little background... a voltage gradient causes a local increase in QVZPE field radiation pressure.... energy from the elevated ZPE field created locally by that voltage gradient in the capacitor plates.

Thanks for that. As a side issue: Though I am totally clueless about Quantum mechanics, I was wondering, however, whether the random QV fluctuations (virtual particles??) are in any way influenced by existing EM fields in that volume of space. Do they have time to interact with any field, or does the field somehow influence their genesis.   From what you say, it seems that there is some influence?

Quote from Ris on January 7th, 2017, 01:07 AM

may be useful
http://energythic.com/view.php?node=208
http://energythic.com/view.php?node=209

Thank you! This does look interesting; "...Thus the input power is not consumed for the propulsion of the liquid, but for producing heat, thus the kinetic energy represents an excess energy that still violates the law of energy conservation."
I'll study this further.

Quote from captainradon on January 12th, 2017, 03:57 PM

Thanks for that. As a side issue: Though I am totally clueless about Quantum mechanics, I was wondering, however, whether the random QV fluctuations (virtual particles??) are in any way influenced by existing EM fields in that volume of space. Do they have time to interact with any field, or does the field somehow influence their genesis.   From what you say, it seems that there is some influence?

Yes, there is an interaction, at the magnetic diffusion rate for whatever material you're working with (in this case, air, and in this case, given the small size, we can assume instantaneous interaction).

EDIT:
----------------------------------------------------
Whoa. I just thought of another 'hole' in my thought processes... an increasing charge density in a capacitor decreases QVZPE field radiation pressure between the plates, just as magnets placed opposite-pole to opposite-pole (N to S) decrease QVZPE density. Thus, as you charge a capacitor, it reaches a point where it can't hold any more charge because an increasing charge density reduces the available capacitance. That decreased quantum vacuum field radiation pressure between the plates creates a tensor stress which tries to pull oppositely charged plates together.

That makes sense, and bolsters my contention (quoted below) that a magnetic field can alter the QVZPE field density and thus alter the available capacitance.
----------------------------------------------------

http://open-source-energy.org/?topic=2640.msg36479#msg36479

Quote

I've been reading:
http://arxiv.org/pdf/1106.3996v1.pdf

It says that as QVZPE field density is reduced, capacitance between two plates decreases. Thus if QVZPE field density is increased, capacitance increases.

This is apparently due to the QVZPE field aligning virtual fermion-antifermion dipole pairs, which accounts for capacitance. Thus in a perfect vacuum (no matter, no QVZPE field), electrical capacitance cannot exist.

Thus, if your wires were shielded via a Casimir cavity, they'd act to transmit the current induced in the center wire, but wouldn't act to counteract that current because they couldn't interact with the QVZPE field between the capacitor plates.

So essentially, you've got an electrical version of the magnetic Casimir cavity I was describing in this post (electricity and magnetism being conjoined into electromagnetism, the two forces are fungible):
http://open-source-energy.org/?topic=1956.msg35008#msg35008

It'd be interesting if a working model of your idea could be constructed... it'd give rise to a whole host of new technology, not the least of which would be DC transformers. It'd be a sort of near-field DC transformer.

Quote from captainradon on December 20th, 2016, 12:29 PM

...a gun, hey?  :D   but only one shot?  :-/ hmmm

Sorry for my flippancy, it was too early in the morning.

If, as you say, the situation in fig 4 is like a one-shot discharge, wouldn't that bring the system right back to its original state?
Because the original charge separation actually cost us nothing, in my view; it was provided for free by the perpetual dipole of the plates.

If we can discharge the inner plates of fig. 4 through the load, we have achieved a tiny bit of free energy, and would return the circuit to it's original state. There would be a bit of switching cost to make and break the wire segment between the plates (is it even necessary?)

I heard Tom Bearden say in one of his videos (https://www.youtube.com/watch?v=eNU3MLqyzPk&t=480s ) that a dipole is an infinite source of power, if the "source dipole" isn't "killed".

solution for the situation number four is Tesla switch