Based on the schematic below and having read the patent and further studies on the architecture of transistors and mosfets in switching circuitry we can now determine which harmonic Stan created so that he can filter that harmonic into his chokes.
This morning I continued my studies of my mosfet but this time I subjected it to a frequency sweep to see where it performed most efficiently under a resistive load at 1v square wave duty cycle pulse.
Mosfets are very grumpy little animals, they produce harmonics in some frequency bands and don't produce hardly any in other bands. The architecture of the chip is responsible for this and that architecture likes to vibrate at one band but hates others, mosfets also absolutely hate being switched at less than 50% duty cycle pulse. It screws up their balance and causes huge distortions in the architecture and its mathematical equasions. This is simple denomination factors where 10 devided by 3 always leaves a value the switch cannot deal with. If the switch is dealing with 12 devided by 3 it always operates better than when it cannot devide voltages correctly. When there is no common denominator the switch gets ugly and harmonics worsen.
Todays sweep of my switching revealed that this particular mosfet likes the band 0-11Khz but when we pass 11Khz there is a sharp drop in voltage amplitude reaching less than 50% of the voltage that was present at 5Khz by the time it reached 20Khz. It had a peak at 3.3Khz then a slight peak at 10Khz at 50% duty cycle. I'm beginning to see that there is something significant about these switches at 10Khz related to their architecture. They absolutely love running at 10Khz!
But the fun really starts when we start to reduce the duty cycle at 5Khz drive frequency
I have uploaded a picture of this process and you can see the 10Khz harmonics increasing when we start to narrow the pulse, 45%, 40%, 35%, 30% and finally 15%. You can see harmonic distortion of the 1v pulse amplitude at each stage.
What is so important about this and what does it have to do with Stans schematic?
You see, what Stan is doing is this: In mode one he pulses 2 optocouplers at 5Khz, one of which has a resistor in series, the other has the cell in series and current passes through both circuits through the water but without the resistor this cannot occur, the resistor is a 50w VP50k and causes a series shunt through the water.
When those optocouplers switch off when they are running at 50% duty cycle the inductors have no voltage and there is no gas production. We know this because the mosfet only produces 10Khz when the duty cycle begins to narrow.
You see, Stan has stated in the patent that the drive circuit runs at 5Khz and the inductors are self resonant at 10Khz, in this case we can only load the coils with energy when there is a 10Khz signal present and the only way that can happen is when we narrow the duty cycle pulse width.
So gas will only begin to be produced when the duty cycle narrows and the self resonant chokes begin to filter 10Khz harmonic out of the mode one 5Khz drive frequency.
As he narrows the duty cycle pulse and produces more 10Khz harmonics the system naturally widens the gate period so that during that gate when the inductors collapse into the cell, their time period in which they do so is set by the pulse width, its a magnificent relationship.
The inductors are wound in such a way that they cancel the magnetic flux field and the voltage will be 90 degrees out of phase. When they offload their voltage into the cell they will try to become a series LC network but Stan's diode makes the voltage unidirectional, the inductors can load the cell but the cell cannot load the inductors. Step charge of the cell can be the only result.
This is just amazing to know and I hope everyone understands what is going on. It is so important to realise that as we narrow the duty cycle pulse the 2nd harmonic begins to dominate the circuit and the chokes will charge at this frequency.
I hope people can understand and if you have any questions just ask away.
This morning I continued my studies of my mosfet but this time I subjected it to a frequency sweep to see where it performed most efficiently under a resistive load at 1v square wave duty cycle pulse.
Mosfets are very grumpy little animals, they produce harmonics in some frequency bands and don't produce hardly any in other bands. The architecture of the chip is responsible for this and that architecture likes to vibrate at one band but hates others, mosfets also absolutely hate being switched at less than 50% duty cycle pulse. It screws up their balance and causes huge distortions in the architecture and its mathematical equasions. This is simple denomination factors where 10 devided by 3 always leaves a value the switch cannot deal with. If the switch is dealing with 12 devided by 3 it always operates better than when it cannot devide voltages correctly. When there is no common denominator the switch gets ugly and harmonics worsen.
Todays sweep of my switching revealed that this particular mosfet likes the band 0-11Khz but when we pass 11Khz there is a sharp drop in voltage amplitude reaching less than 50% of the voltage that was present at 5Khz by the time it reached 20Khz. It had a peak at 3.3Khz then a slight peak at 10Khz at 50% duty cycle. I'm beginning to see that there is something significant about these switches at 10Khz related to their architecture. They absolutely love running at 10Khz!
But the fun really starts when we start to reduce the duty cycle at 5Khz drive frequency
I have uploaded a picture of this process and you can see the 10Khz harmonics increasing when we start to narrow the pulse, 45%, 40%, 35%, 30% and finally 15%. You can see harmonic distortion of the 1v pulse amplitude at each stage.
What is so important about this and what does it have to do with Stans schematic?
You see, what Stan is doing is this: In mode one he pulses 2 optocouplers at 5Khz, one of which has a resistor in series, the other has the cell in series and current passes through both circuits through the water but without the resistor this cannot occur, the resistor is a 50w VP50k and causes a series shunt through the water.
When those optocouplers switch off when they are running at 50% duty cycle the inductors have no voltage and there is no gas production. We know this because the mosfet only produces 10Khz when the duty cycle begins to narrow.
You see, Stan has stated in the patent that the drive circuit runs at 5Khz and the inductors are self resonant at 10Khz, in this case we can only load the coils with energy when there is a 10Khz signal present and the only way that can happen is when we narrow the duty cycle pulse width.
So gas will only begin to be produced when the duty cycle narrows and the self resonant chokes begin to filter 10Khz harmonic out of the mode one 5Khz drive frequency.
As he narrows the duty cycle pulse and produces more 10Khz harmonics the system naturally widens the gate period so that during that gate when the inductors collapse into the cell, their time period in which they do so is set by the pulse width, its a magnificent relationship.
The inductors are wound in such a way that they cancel the magnetic flux field and the voltage will be 90 degrees out of phase. When they offload their voltage into the cell they will try to become a series LC network but Stan's diode makes the voltage unidirectional, the inductors can load the cell but the cell cannot load the inductors. Step charge of the cell can be the only result.
This is just amazing to know and I hope everyone understands what is going on. It is so important to realise that as we narrow the duty cycle pulse the 2nd harmonic begins to dominate the circuit and the chokes will charge at this frequency.
I hope people can understand and if you have any questions just ask away.