The square law of voltage, harmonics and relationship to impedance.

nav

The square law of voltage, harmonics and relationship to impedance.
« on November 22nd, 2015, 04:38 AM »Last edited on November 22nd, 2015, 04:46 AM
Everyone at some stage must wonder where Stan Meyer, Nikola Telsa, Eric Dollard and Henry Moray get their respective 'extra' energy from. Well here is an explanation as to where it comes from and why we get it.
Ohms' law and Lens' law in classical electronics tells us that basically current in any equasion is a catalyst into a diminishing algorithm. All calculations that involve current diminish into infinity.
As a simple example of this we will look at the relationship of current and harmonics in the real world then look at their relationship in a free space model.
Applying Ohms' law to harmonics is relatively simple, we can work out perfectly each harmonic in terms of percentage of the original signal source, its loss in dbi throughout the harmonic scale and the voltage will diminish as a square law relationship with harmonic distortion devided by current. This will give you the calculations for dc resistance of a half  phase or impedance of the full phase of ac energy.
We know all this but lets see what happens in a free space mathematical model:
A free space mathematical model is a situation where we calculate the same laws but where there are no wires where current can enter the algorythm and so dc resistance and ac impedance are basically taken away from the equasion. This gives us an idea of what harmonics and its square law to voltage try to naturally achieve.
If you start with a wireless inductor operating at a certain frequency and the inductive value is equal to the capatitive value based on our knowledge of Ohms' law without harmonic distortion, the output voltage will remain equal to the input voltage because there is no catalyst to change the algorythm. This would also be the same in a wireless transformer because there is no current exchange.
Now lets examine harmonic distortion in the same model. If you create an input frequency that has a full range of harmonic distortions towards infinity, this is what happens.
If you have a wireless inductor of 5khz input frequency the output voltage devided by time is equal to the input voltage devided by time. If the input frequency is stopped and the wireless inductor vibrates at the second harmonic of 10Khz,  the equal capacitive and inductive nodes are doubled but are devided by the same amount of time. This doubles the output voltage. If there is a third harmonic it trebles it so on and so forth.
This will not stop until the harmonic distortions diminish but in a world with no wires the harmonics are infinite and their square law with voltage is also infinite.
So when current is zero and we cannot apply current into an equasion, if there are no harmonics present the output voltage will remain the same as the input voltage at a certain frequency but when harmonics are applied,  because of their square law with voltage, will double the input voltage at every harmonic level towards infinity.
If we come back to the real world of wires and resistance and reintroduce current into the equasion, Ohms' law will diminish the voltage back from infinity into reality and resistive loss.
How do we get around this?
We need to create a reality where current is no longer part of Ohms' law and where voltage takes off towards infinity square to harmonics. To do this, firstly we must cancel current. To cancel current we must make two opposing current fields cancel each other out so it is impossible for linear activity to take place.
If you build a series circuit that is fed by 5Khz input into a capacitor Ohm's law will apply for the loading of that capacitor, if you add a series inductor into that circuit and it performs with the capacitor, Ohm's law will still apply. You will not win!
If you build a choke that is self resonant at twice the input frequency, that is the second harmonic of the fundamental frequency and you build it with two inductors that are wound in such a way that they cancel the each others flux field out, when those chokes filter that second harmonic they will do so in a condition where current is not present in the algorythm of Ohms' law and they will double the input voltage.
Now, because current remains at zero, the third harmonic, the fourth harmonic and every possible harmonic in an infinite direction will also be filtered into those inductors and even though Ohms' law deminished them before they got inside the inductors in the wiring of the series circuit, it does not matter, even if the 7th harmonic was very weak it will still increase the input voltage by a factor of 7 and the 23rd harmonic will increase the input voltage by a factor of 23 and it will keep going towards infinity if the wiring of the series circuit allowed it to do so.
Now, getting the voltage out of the inductors into a load is a difficult factor that needs to be thought about. When those inductors collapse it is impossible for them to collapse in a linear motion, they can only collapse 90 degress out of phase with the current which has been cancelled by opposing flux fields. So we now have high voltage 90 degrees out of phase with current at each terminal of the inductors. The only way to ensure that current doesn't come back into the algorythm is to match the condition of the inside of those inductors on the outside of the inductors. That means you match the real world impedance of the coils in the wiring to the cell and the cell also matchs the real world impedance or both match it together as one. To match the coils impedance then it has to fall into its resonance too, so the total length of the wires and the tubes together must be just under a quarter wave of 10Khz because less than a quarter wave is capacitive in nature but above a quarter wave is inductive. If you extend the impedance and resonance of the coils to the tubes, current cannot enter Ohms' law again. So what we are looking at is a shortened transmission line with little losses.
I hope this has given people a better understanding of how voltage sets off towards infinity and its square law to harmonic distortion and the importance of resonant impedance matched transmission lines.







nav

Re: The square law of voltage, harmonics and relationship to impedance.
« Reply #2, on November 22nd, 2015, 09:39 AM »Last edited on November 22nd, 2015, 09:43 AM
It is important to read Stan Meyers patents and fully understand what is going on. If you look at the picture which Russ kindly supplied there are a few things going on that need to be explained.
Firstly, you notice nine switches which indicate that the outer tubes of the cell are wired in parallel through the switches. The inner tubes are wired differently, they are still in parallel but because he only switches the positive side, he uses a common ground for all nine inner tubes.
Right, about the brown staining of the tubes: There are two modes of operation in the VIC, the first one is based at 5Khz and is a normal mode of operation that uses the cell as a short circuit to pass current around the series circuit. The second mode of operation is paracitic of the first mode in which harmonics starting at 10Khz and all subsequent harmonics that the series circuit allows are filtered into the two chokes then during the gate period are released at resonance into the cell but on the outside of the inner tube and the inside of the outer tube which remain shiney. The staining is iron oxide and you can see it all over the top spacer. That oxide has been caused because of the following effect: During normal mode which is mode 1 at 5Khz, current passes through the water in between the tubes with a skin effect using the outside surface of the inner tube and the inside surface of the outer tube. During that ionic process, the rest of the tubes are coated in iron because of the anode and cathode effect of electrolysis. When mode 2 turns into a capacitance of high voltages the iron coating is blasted away with high speed Oxygen and Hydrogen molecules, So in essence mode one coats the tube with iron but mode 2 removes it. However, the voltage field that causes the Oxygen and Hydrogen in between the tubes is restricted to that region and so the iron coating in the inside of the inner tube and outside of the outer tube will not be removed and that is exactly what we have.
You also notice that the outer tubes have slots cut in them. This is the method he used to fine tune the tubes into resonance and the same technique is used for tuning resonant cavity filters that remove common mode currents from transmission lines. He uses a wiper arm inductor to vary this together with varying frequency when different amounts of tubes are used, the PLL follows these factors.
Now about the winding of Stans inductors. If we are removing common mode currents which contain the harmonics we are interested in then the inductors are would opposite on the same toroid core, this will cancel the flux field and current will be zero.
If there are harmonics present which are not common mode ie normal current harmonics then in order to filter those harmonics we would need to wind them the same way but I doubt that is the case. I believe that the strongest harmonics are common mode currents and I have captured these harmonics at 3khz with disastrous consequences because I didn't match their impedance and resonance properly and reintroduced current back into the equasion. If there are ANY impedance spikes in your system they will flyback at the input or light the cell up like a Roman candle. I believe Ronnie has experienced this already like I have, remember to stay safe.

nav

Re: The square law of voltage, harmonics and relationship to impedance.
« Reply #3, on November 22nd, 2015, 09:55 AM »Last edited on November 22nd, 2015, 09:58 AM
Here we see mode 1 ionic staining on the tubes and white spacer.
We see the inner tubes have a common parallel ground and the resonant filter tuning slots cut in the outer tubes which indicate Stans cells behave the same way as resonant cavity filters in a transmission line.




nav

Re: The square law of voltage, harmonics and relationship to impedance.
« Reply #7, on November 23rd, 2015, 05:55 AM »
Quote
Nav, you are doing a great job. Everyone can learn form this information.
Thanks Ronnie.
There are so many people failing at replicating Stan's work it is unbelievable, the reason we are failing is because we do not understand this technology. We have all tried various different set ups with no success or maybe a little success, I myself have theorised different possibilities and different ideas hoping to inspire a realization in someone, it is important to keep people inspired and keep them believing Stan's work can be done because this road is long.

This particular endevour is different however. It's different because members can now begin to grasp how Stan's networks operate. Not only that, because we are beginning to understand paracitic currents and how to store them in current chokes with muliplying voltage in a current free algorythm, you don't need Stan's schematics anymore. You can design your own schematics that don't even operate fuel cells but other apparatus. The mathematical free space model shows us that voltage is square to the infinite path of harmonics when current is kept from the equasion. We know how to cancel current in bucking coils, cmc chokes and series current chokes but we don't know what to do with the voltage field and its working condition.
The working condition is the keys to the kingdom. Since 1970 we have been drilled and taught to keep away from cmc's and their respective harmonics at all cost and we've been shunting them to ground not even caring to think if they could be useful. We've been creating cmc chokes that cancel current with opposing flux fields and shunting out of phase voltage to ground without even understanding or measuring the energy we are wasting or looking at its potential. The reason we have done this is because we never realised that the voltage field needs a working condition to flourish that extends the current free algorythm from inside the inductor to the outside network.
Yet we play around with transmission lines all day understanding perfectly the concept that the oscillator impedance must match the line and antenna impedance at 50 Ohms and that the antenna resonance must match the oscillator frequency or the whole transmission line will fail!
If you know this information then you already have the keys to the kingdom where the inductor voltage is concerned. You see, Stan takes the voltage from his chokes and matches their impedance with the line and the antenna, the antenna being his tubes. He matches the frequency of the chokes with his tubes so they are resonant and the whole thing acts like a shortened transmission line like Ronnie has being telling us all along.
But there is a difference, in a normal transmission line you need voltage and current to transmit, this system has no current so it cannot transmit but it will still act like a transmission line. If your resonant line and antenna (tubes) are cut just short of a quarter wave then they will become capacitive in nature and they will try to form a resonant series LC network with the inductors. The problem is, Stan has placed a diode in the series circuit so the inductors will load the antenna but the antenna cannot load the inductors. That means that during every gate period when the inductors become self resonant the diode becomes a switch because it allows the inductors to charge the antenna but not the antanna to charge the inductors and there is only one thing that can happen from here on in - the inductors will step charge the antenna with no reply. Ain't that right Ronnie?
People messing around with flat plates - it will not work, people messing with tubes that are not capacitive and are not cut less than a quarter wave of the inductors self resonant frequency - it will not work, ain't that right Ronnie?
So to sum up this system: You need to create a series VIC circuit on a toroid with a secondary and two chokes connected to the fuel cell. The chokes will be self resonant at 10Khz and wound so that the flux fields cancel each other out.
But here is a little secret about the chokes: The more windings on the chokes the higher the voltage will be at resonance of 10Khz. The reason is because there are more distributed C and L nodes and always remember our square law - when current = zero, voltage doubles at every harmonic level. So if you make your coils self resonant at 10Khz, 15Khz, 20Khz etc etc the voltage is expotential. Just make sure that you reach the minimum for resonance. A coil that has 1500 windings that is self resonant at 15Khz will produce the same voltage as a  coil that has 4500 windings on and self resonant at 10Khz but when the latter coil vibrates at 15Khz, 20Khz, 25Khz the voltage takes off towards infinity square with harmonics.
The VIC operates in two basic modes:
Mode 1. Normal current passes through the VIC and through the cell at 5Khz provided by a dirty bridge rectifier and mosfet, this current is high enough to pass through the water. While this series current takes place the chokes are loading with cmc's all through the harmonic range related to 5Khz and its dirty harmonics.
Mode 2. When normal current shuts down from the dirty mosfet, the chokes sense a change in current and collapse at their own self resonant frequency into the tubes. Because there is no current available (the flux field is cancelled in the toroid) the voltage is 90 degrees out of phase and will enter any system that contains its working condition. The line impedance and antenna are a impedance match as well as a resonance match, the chokes will try and form a series LC network with the tubes but we know the diode only allows it to go one way so it step charges the cell.
Based on my current free calculation minus losses in a less than perfect impedance match, also based up to the 23rd harmonic as being the last, wound on inductors that at are exactly double the input frequency is 126960v per second from 12v input @ 500ma in mode 1.
@ the 8th harmonic which is more realistic is 15360v per second
@ the 3rd harmonic 2160v per second
Those figures were based on a 20:1 step up transformer@ 500ma
At step up based on 40:1@ 1000ma the figures are:
@ the 3rd harmonic 4320v per second
@ the 8th harmonic 30720v per second.
If you allowed these voltages to enter an untuned network it will light it up like a firework.
Be very careful!