And Dr. Stiffler in 2008, burning some more water generated with just milliwatts of power input.
https://www.youtube.com/watch?v=DTgY3GbGRs0
https://www.youtube.com/watch?v=DTgY3GbGRs0
Basically I just cant reconcile stans 50khz to the speed of sound in water and stans tube dimensions using what ( I think!) is correct maths. I can reconcile it using incorrect maths!!!
My hunch is the 50kHz (or less) isn't mechanically related to the water splitting process. This relatively low frequency is related to the self resonance of the water cavity electrically. This is a frequency at which the water cavity is no longer a dead short and in such a state can be charged up to relatively high voltages. Once charged, the resonant condition can be halted, at which point the water cavity becomes a dead short upon itself.
So suppose we get 20 KV charged across the water cavity with Re of 78.54 ohms. At the moment we drop resonance, 254 amps of current now has no place to go except directly into the water. That's 5,092,946 watts of power dissipated internally into the water. Five million watts! Evolution of HHO is a must-be condition for that very brief interval. Once gas evolution has rolled off, we again go back to a resonant condition and recharge the water cavity. The cycle repeats, trading voltage for gas output.
please enlighten me with these numbers
thats an interesting method to get power and current, Matt but I'm not sure if it is an accurate
way to determine current that is generated in the water when the dipoles relax.
I think to determine the current generated would be extremely complex procedure.
Resistance of water in ohmns, there is table here gives some values:
http://www.aquaread.com/need-help/what-are-you-measuring/resistivity/
So lets try pure water, resistance: 20megaohmn
and voltage stan mentions 5kv on that last video from irondmax,
plugging those values in you get :
current: 0.25amp
power: 1.25watts
Obviously not what you want, I haven't started to look into what sort of currents are created when a charged water capacitor, discharges into itself. Its certainly something I'm interested in, but would take quite a bit of research to find out exactly how that occurs, and then there would be complex maths behind determining any values.