Hi, all. I just had an epiphany. I'll try to lay it out as simply as I can.

Ok, so we're trying to split the water molecule, right? And we know that under resonance, things tend to fall apart. But how do we find the resonance of a water molecule?

We use Quantum Mechanics.

In a prior post, I wrote:Quote So let's lay out the equations:

E

E=mc

E=hf

E=Pc

We know the mass of each element making up water (hydrogen and oxygen), so we can use:

hf=mc

Thus, f = (mc

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EDIT: I just learned that this is called the Compton wavelength (actually, it's inverse, the Compton frequency)... there is also the reduced Compton wavelength (and in this case, the increased Compton frequency). In the case of the wavelength, you'd divide by 2*pi. In the case of frequency, you'd multiply by 2*pi. This gives you the "spin frequency / wavelength" of one radian, whereas the Compton wavelength and Compton frequency give you the "spin frequency / wavelength" of a full 360 degree circle.

Think of the ramifications of this... light, curling in upon itself into a self-perpetuating loop, generates mass. Shrodinger, Einstein, Klein, Gordon, Compton... they all used this reduced Compton wavelength to describe matter in a quantum sense... it's the geometrical transform between light (energy) and matter. This is the underlying reason why we know matter can be converted to energy, and energy can be converted to matter. The light is still moving at c, but it's going nowhere from the perspective of an outsider, thus it's perceived as matter.

This frequency is the necessary frequency to convert that matter back into energy. We definitely would want to use a lower harmonic. :D

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This gives us the resonant frequency for hydrogen and oxygen if they were standing alone.

What one must do after that is figure out what the total system resonant frequency would be based upon the total mass of the water molecule using the same equation above, then check to see if there are any harmonics between the resonant frequency of the water molecule and the resonant frequency of either the hydrogen or oxygen.

I'm betting that hitting the water molecule with one of those harmonics would cause it to dissociate.

Ok, so we're trying to split the water molecule, right? And we know that under resonance, things tend to fall apart. But how do we find the resonance of a water molecule?

We use Quantum Mechanics.

In a prior post, I wrote:

Of course, E=mc^{2}is incorrect (not so much incorrect as incomplete). It doesn't take into account massless entities. It's only valid for massive objects. In 1905 Einstein derived an equation that works in all situations:

E^{2}=P^{2}c^{2}+m^{2}c^{4}.

He also figured out that light is both a particle and a wave, and that the energy of a photon isn't governed by its mass or its velocity (like matter), but instead is governed entirely by f, its frequency: E=hf, where h is Planck’s constant.

For light, m=0, so E=Pc (energy and momentum are proportional). Notice that massless entities can never have zero momentum, since something with zero mass and zero energy isn't something, it’s nothing. This is just another way of saying that light can never be stationary (ie: light has no "rest frame"). It's also a way of saying that everything (massive or massless) has frequency.

In the case of an object with mass m, that isn’t moving (P=0), you then get E=mc^{2}.

E

^{2}=P^{2}c^{2}+m^{2}c^{4}E=mc

^{2}E=hf

E=Pc

We know the mass of each element making up water (hydrogen and oxygen), so we can use:

hf=mc

^{2}**h**is Planck's constant, 6.626^{-34}joule-second.Thus, f = (mc

^{2})/h.--------------------

EDIT: I just learned that this is called the Compton wavelength (actually, it's inverse, the Compton frequency)... there is also the reduced Compton wavelength (and in this case, the increased Compton frequency). In the case of the wavelength, you'd divide by 2*pi. In the case of frequency, you'd multiply by 2*pi. This gives you the "spin frequency / wavelength" of one radian, whereas the Compton wavelength and Compton frequency give you the "spin frequency / wavelength" of a full 360 degree circle.

Think of the ramifications of this... light, curling in upon itself into a self-perpetuating loop, generates mass. Shrodinger, Einstein, Klein, Gordon, Compton... they all used this reduced Compton wavelength to describe matter in a quantum sense... it's the geometrical transform between light (energy) and matter. This is the underlying reason why we know matter can be converted to energy, and energy can be converted to matter. The light is still moving at c, but it's going nowhere from the perspective of an outsider, thus it's perceived as matter.

**E**^{2}=P^{2}c^{2}+m^{2}c^{4}This frequency is the necessary frequency to convert that matter back into energy. We definitely would want to use a lower harmonic. :D

--------------------

This gives us the resonant frequency for hydrogen and oxygen if they were standing alone.

What one must do after that is figure out what the total system resonant frequency would be based upon the total mass of the water molecule using the same equation above, then check to see if there are any harmonics between the resonant frequency of the water molecule and the resonant frequency of either the hydrogen or oxygen.

I'm betting that hitting the water molecule with one of those harmonics would cause it to dissociate.