Do you mean an air gap in the magnetic core?
I think that can help to rise the voltage. In my tests, there were no air gaps but also no very high voltage.
But as you see in the original VIC there is a option to "fine tune" the air gap with help of the magnetic cores and a little drill hole (marked in pic) to adjust the air gap. (Attachment1+2: VIC)
Also the 8XA Bifilar Coils have this air gap. (Attachment 3: 8XA)
So IMHO it looks a litte bit, that Meyer was using his transformer as a flyback converter or something.
You are welcome :)
. Hopefully this can help someone.
Yes that's the point, but always there will be a chain.
If more frequent enough, the chain had fallen quite, but will point out, because the potential remained whole, the inductor, and the cell received only a fraction.
Forget for a moment Meyer. And let's use what we know:
An inductor to be charged, must have current (imagine an LR circuit), turn on and off very slowly, there will be a lot of current, turn on and off very fast, there will be little current, but in both cases will be out of resonance.
The point is correct: when the time is bound coincides with LR load time.
The cell is not like a resistor (nonlinear), I think like an R-NTC. Much like a diode (at least driving the curve). Try to make a model in the simulator, and that could'll know when the oscilloscope waveform that appears, I showed the first picture.
Yes, the curve of the water is like a diode. :-/
So IMHO we have to inhibit the amps as much as possible.
The first point IMHO is that we can gain Z (Impendance) in the circuit, so we can inhibit the amps very good. Because the WFC is in series with the Z, the amps which going through the water are also inhibited. So energy will not be consumed.
For example: Z can be increased by the frequency or the inductivity, as you said.
The advantage of the inductivity is, that the energy isn´t lost.
The next point is, when we look at a secondary of a transformer, what will happen if we gain Z on the secondary-->the voltage will rise, because when the transfered energy from the primary side will result always as P=UxI (Voltage*Current). So P is constant because of the primary, that means when current is very low, the voltage will rise automatically.
This will inhibit electrolyses for the first step and also increase the voltage. The other point is, that we have a gap in our tube. The current can not go through the water because of the resistance. But the voltage will pending on the pysical existing capacitor (WFC).
Voltage is only a force on the electrons on the watermolecule and will pull out the electrons of the bonding (ionisation). The product of this chemical reaction ist H2 + O2 because they lost their bonding. The Electron extraction circuit (EEC) of Meyer would have never worked, when there is no iosinsation (pull out electrons of the water).
There are also other ionising reactions e.g. creating ozon O3. Ionise O2 and you will get O + O that will form with other O2 to an endproduct O3.
(So Thats my theory, don´t hit me :)