31

##### Stan Meyer WFC / Re: The AM signal and how it works. Carrier and modulation

« on September 30th, 08:52 AM by**nav**»

Nice Nav, Thousands of words there, Of coarse I ask for video or pic?

32

##### Stan Meyer WFC / Re: The AM signal and how it works. Carrier and modulation

« on September 30th, 08:37 AM by**Lynx**»

That's amazing Nav, many thanks for sharing

Good to see you again

*:thumbsup:*Good to see you again

*:-)*33

##### Stan Meyer WFC / Re: The AM signal and how it works. Carrier and modulation

« on September 29th, 06:19 PM by**securesupplies**»

Nice Nav, Thousands of words there, Of coarse I ask for video or pic?

34

##### Stan Meyer WFC / Re: The AM signal and how it works. Carrier and modulation

« on September 29th, 08:51 AM by**nav**»

Also the inductance figures on this chart are totally made up, the chart is pure fiction.

35

##### Stan Meyer WFC / Re: The AM signal and how it works. Carrier and modulation

« on September 29th, 08:48 AM by**nav**»

In other words the chokes will not pass current at 5khz.

36

##### Stan Meyer WFC / Re: The AM signal and how it works. Carrier and modulation

« on September 29th, 08:37 AM by**nav**»

Look at the chart, the resistance figures for L1 go up in frequency but is only 100 oms at 100hz where its resistance is at 1khz is 3.1kohms and 10khz is 1200kohms, what figure is missing from the chart? It's self resonant frequency where the resistance goes off the chart which is 5khz. 10khz is double the resonant frequency. They failed to mark its resonant frequency in the chart, why?

The carrier frequency is close to mains electric which is 50/60hz and the modulations are close to 5khz. I'll tell you what is totally fake on the chart, the secondary, L1 and L2 are closely matched in impedance at 1khz at around 2.5kohm/3kohm yet when we switch to 10khz the secondary is at 190k yet L1 and L2 have jumped to 1200k each, this is totally impossible and the true figures for L1 and L2 are 205k and 170k respectively at 10khz because I've measured them. What did they try to hide? They tried to hide the fact that L1 and L2 are coming into resonance as you approach 5khz. At 5khz L1 and L2 are approaching 10,000kohm and it depletes back down as you approach 10khz again.

The carrier frequency is close to mains electric which is 50/60hz and the modulations are close to 5khz. I'll tell you what is totally fake on the chart, the secondary, L1 and L2 are closely matched in impedance at 1khz at around 2.5kohm/3kohm yet when we switch to 10khz the secondary is at 190k yet L1 and L2 have jumped to 1200k each, this is totally impossible and the true figures for L1 and L2 are 205k and 170k respectively at 10khz because I've measured them. What did they try to hide? They tried to hide the fact that L1 and L2 are coming into resonance as you approach 5khz. At 5khz L1 and L2 are approaching 10,000kohm and it depletes back down as you approach 10khz again.

37

##### Stan Meyer WFC / Re: The AM signal and how it works. Carrier and modulation

« on September 29th, 08:01 AM by**nav**»

Now for those of you who want ball park figures, the total electrical resistance of Stan's secondary, L1 and L2 is roughly 220ohms. Have you seen this figure before? What does that tell you about the carrier frequency?

The electrical resistance of L1 is 77 ohms

The electrical resistance of L2 is 70 ohms.

What does this tell you about Stan's tubes? Their electrical resistance including the transmission wire is roughly 7 ohms. What does that tell you about whether they are in series or parallel? If they are in parallel what is the reactance of the system as you switch more sets of tubes on, will it remove the need for L2 to be variable? Those would be the questions I'd be asking myself.

The electrical resistance of L1 is 77 ohms

The electrical resistance of L2 is 70 ohms.

What does this tell you about Stan's tubes? Their electrical resistance including the transmission wire is roughly 7 ohms. What does that tell you about whether they are in series or parallel? If they are in parallel what is the reactance of the system as you switch more sets of tubes on, will it remove the need for L2 to be variable? Those would be the questions I'd be asking myself.

38

##### Stan Meyer WFC / Re: The AM signal and how it works. Carrier and modulation

« on September 29th, 07:34 AM by**nav**»

So, in simple terms if you create a positive choke that is self resonant at a modulation frequency of 5khz and the choke is 500 yards of 30 gauge wire, the demodulation would be 5khz and the cell plus the negative choke would be 500 yards long plus a means of fine tuning. Hope people understand now. Those are not true wire length figures BTW just examples.

39

##### Stan Meyer WFC / Re: The AM signal and how it works. Carrier and modulation

« on September 29th, 07:08 AM by**nav**»

The water fuel cell is by definition half of an AM transmitter. By that I mean that there is a voltage maxima and capacitance but there is no current maxima and no inductance. A normal AM antenna has voltage maxima and voltage minima, current maxima and current minima, it has an inductance field and a capacitance field. The water fuel cell lacks current and induction therefore it cannot transmit the AM signal. The reason it has voltage is because the chokes cut off the current and induction but allow voltage and capacitance through the same resonant action as any AM transmitter. Every AM transmitter must match the transmission line (coax) impedance and the antenna impedance to the oscillator impedance. Stan's system has to match the oscillator frequency (chokes) to the line frequency (wires from chokes to cell) but not the antenna frequency (water fuel cell). I'll tell you why you don't need to match the water fuel cell. In a normal transmitter, the impedance of the oscillator, transmission line and antenna is usually 50 ohms (not high impedance). The antenna on a 11m 27mhz system is naturally about 1000 ohms on a shunt fed and 75 ohms on a dipole and a matching section is needed which will bring the impedance down to 50 ohms and match it. If you don't do that you get standing waves which will reflect the signal back at the oscillator. If Stan's system operates at 5khz on the modulation frequency which is the resonant frequency of the chokes then the incident wave would be miles in length, the incident wave for 27mhz is 35 feet, as you come down in frequency in the incident wave goes up exponentially and 5khz would present an incident wave of 93600 feet. It doesn't matter if you cut the cell tubes to half waves or quarter waves or 32nd waves you would never get them big enough to tune to resonance and impedance match to 5khz, totally impossible. There is only one way to do it and that is use the negative choke as a impedance match but at less than a quarter wave. That means that the total length of the tubes which are acting similar to a dipole array in series with the negative choke are just under a quarter wave of 93600 feet. A 32nd wave works out at 975 yards total for negative choke and cell in series as in impedance match through a dc ground system. a 64th wave works out at 487 yards for the cell and negative choke. In transmission systems, anything less that a quarter wave is purely capacitive and that's part of the reason the cell takes on voltage. That is why the length of the tubes is not important and why the negative choke is variable in some cases - it's an AM impedance match.

40

##### Stan Meyer WFC / Re: The AM signal and how it works. Carrier and modulation

« on September 29th, 06:12 AM by**nav**»

Lets just talk a little about self resonance and Q factor. The more efficient a coil is at forming tank circuits then the longer those tank circuits will last. The resistance of the wires plays a huge roll in this and ultimately super conductors that offer zero resistance will help and technically speaking if there is no resistance in the wire at all and the Q factor of the coil was high enough and the efficiency of the capacitor is high enough then the tank could swing forever. We all know this is impossible and Stan always talks about the efficiency of components as being the only reason we cannot reach infinite voltage. The capacitor components and coil components would all need to be super conductors besides the connecting wires and it would have to be performed in a vacuum. That's not going to happen. If you want an efficient system that can resonate efficiently enough to perform the work that Stan is talking about then you need an high quality factor otherwise the voltages won't get high enough and quick enough. This means the choke wire has to be top quality and it has to have low minimum damping. BUT here is the most important bit, the wire which connects the chokes to the fuel cell - the higher the resistance then the higher the damping within the choke. What does this tell you? It tells you that resistance between the choke and water fuel cell (in de ionized water) is the absolute enemy. Even though the fuel cell may present an high impedance to encourage a tank circuit, the connecting wires are presenting a lower impedance. Lower impedance causes current flow in a system where you are trying to form a tank circuit and throws the system out of resonance. Therefore the connecting wires need to be the same resistance and inductance as the coil material with no impedance spikes anywhere along the way so that the wires are part of the coil. When you wind your chokes let the choke wire extend to the cells but insulate against short circuits. DO NOT increase or decrease the gauge of your wire connecting choke to cell, it will cause standing waves because of an impedance mismatch, the standing waves will reflect the voltage back towards the chokes and burn them out by inducing current.