new oscillator circuit shared By Nelson Rocha

Matt Watts


evostars

Re: new oscillator circuit shared By Nelson Rocha
« Reply #327,  »
I now have MnZn ferrite rods to increase the inductance on the outside of the l1 and l3 coils. the rods are placed radially on the coil. 8 rods per coil.

Also ordered liquid latex but that will arrive next year
Re: new oscillator circuit shared By Nelson Rocha
« Reply #328,  »
I wondered about how to connext the new l2 coil.
it exists of 2 series connected bifilar coils.

I wondered about getting the highest voltage difference between the windings, but also want to keep the polarity in order.

So I will simply go from left to right.
Re: new oscillator circuit shared By Nelson Rocha
« Reply #329,  »Last edited
When L2 is resonant, the resonant sine provides additional voltage between the positive and negative impulse.

the max impulse is limited by the avalanche rated body diode (500v)

but with l2 being resonant the voltage is added, and the total impulse voltage can reach higher.

therefore the voltage difference needs to be biggest, to get the max dielectric field strength.
this way the impulse volt differnce is also max

ti get the max resonant voltage rise in l2, the c5 cap should not be to big.
the c6 cap should be relatively bigger than c5

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Re: new oscillator circuit shared By Nelson Rocha
« Reply #330,  »
making new l2 coil, made of 0.4mm2 wire, played with it but resistance is ti high, 1.6 ohm.

want to make another from the 0.75mm2 wire. 2x 5m
but this time really flat. 1 wire thick x2
that has lower resistance.

I will have to split the speaker wire in 2. I wonder about the 5m, as one winding probably will need slightly more. but I will ignore that.

pictures are from the latex cast im makimg

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impulse idea
« Reply #331,  »
L2 has a poitive impulse on the c5 side
and a negative impulse on the c4 side.
(when above the series resonant frequency).

What if connected two separate plates from these two ends of l2.

make a hole in both the plates,
put a dielectric in between the plates,

and add some smoke. would it be deviated at the hole, by the pulsating field?
Re: new oscillator circuit shared By Nelson Rocha
« Reply #332,  »
0.4mm2 latex coils.
not perfect.
when stacked, there still is an air layer.
would need another cast of latex to seal it.

but this wire is to thin giving to much resistance. will not use it. learned a lot

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Re: new oscillator circuit shared By Nelson Rocha
« Reply #333,  »
already made new L2 from 2x 5 meter speaker wire. spilt the 2 wires up, and made a 1 wire thick bifilair coil x2

this has much lower resistance. 0.75mm2

the 2 bifilar pancakes will be stacked.
and series connected into 1 coil.

I could make a mould to cast the latex in. gipsum would be the best as it soaks up the moist.

but first I would need to know the perfect distance.

best would be to make a single cast of l1 l2 and l3 stacked. but its much to soon for that.

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new setup with ferrite rods
« Reply #334,  »
I have equal l1 l2 l3 bifilar coils.
all are stacked. l1 bottom l2 middle.
all are 15mm distanced

under l1 are 8 MnZn ferrite rods
on top of l3 are 8 MnZN FERRITE rods.

now I can tune l2 for max resonance with c5. giving max current.

If I now add parallel capacitance to l3 (with a 5w load) it DOES NOT change the l2 resonant frequency! thats great.

L1 north is facing l2
L1 is physically reversed to l2/l3 (counter rotating)

finally progress again. thank god for these ferrite rods

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Re: new oscillator circuit shared By Nelson Rocha
« Reply #335,  »
with 5w load, l2 amps only rise to 2.3A
with 21W load l2 amps rise to 5A.
load is 12v bulb.

dc input power also rises to 1 amp from. 0.45A at 12.4v dc
Re: new oscillator circuit shared By Nelson Rocha
« Reply #336,  »Last edited
the current in l3 is a sine that is only positive, and is double the frequency of l2.
Why is it an octave higher?

could not be a response to the impulse of l2. if I tune l2 to max resonce without impulse its still double the frequency

no! l2 is still having a negative impulse on the c4 side. I need to reconnect l2 so the negative side is facing l1.
positive impulse side of l2  should be facing l3
Re: new oscillator circuit shared By Nelson Rocha
« Reply #337,  »
reversed l2 coil, so negative impulse faces l1, no change, l3 current is still double frequency positive biased
Re: new oscillator circuit shared By Nelson Rocha
« Reply #338,  »
ah me stupid...
l3 was measured rectified without caps...
progress
« Reply #339,  »
Learned much today.

L2 L3 must be close coupled.

L1 L2 must be distanced 15mm for lowest current draw. L1 must be reversed, north facing L2

Ferrite rods on both sides of L1 works best (8 above 8 below, radial MnZn ferrite rods).

L3 output must be full rectified.  DC signal must be grounded, and then 35uF caps is enough to stabelise the DC voltage. This makes it easy to read the power (DC).

I now have 44nf on C5, this gave the highest current in L2 But might need to tune more (didnt have 1nF tuned with 10nF)

L3 load is now 41W 230V halogen lightbulb. It even becomes brighter when the rectifier DC cap of 36uF is added (and 1 side is grounded).
DC really needs earth ground, else it wont rectify.

C6 is now 50nF didnt tune this one, so still able to play with it. (tune).

Lamp is very bright. but input amps also are still pretty high. (input power was 1,5A 24V, 36W)
 
First need to fine tune L2 with c5 for max current while c6=0
Then start tuning c6.

Somehow the power supply goes bezerk when tuning. ch1 is not connected, but suddenly the relais activate, and ch1 shows current and voltage.
might remove the ground connection I made to the negative og the power supply.
Very strange behaviour.

With 12V 21W load. adding C6 didint detune L2. very promising. might need to go back to that lamp, but it restricts the voltage. current goes up. Feel I need the higher voltage from the 41W 230V halogen bulb.
Re: new oscillator circuit shared By Nelson Rocha
« Reply #340,  »
yes with the 12V bulb the sine in L3 is clipped into a square wave of only 10V, giving 8V rectified DC.
Adding capacitance into c6 then doesnt change the L2 res freq, as the voltage of L3 barely changes.
Makes life easy.

So tuning C6 while L2 stays the same.
but first tune C5 for max current.

current of L2 is the same as in L3. more amps is better.
Re: new oscillator circuit shared By Nelson Rocha
« Reply #341,  »
Did a lot of tuning with the 21W 12V bulb.

after a while I disconnected the dc ground of L3. I noticed the sine wave returned. still the dc voltage didnt change.

The sine wave had a negative spike on the top. So the L3 coil sees the negative spike. At this moment I tuned it so the possitve spike was really small. But I tuned C2 to 1nF so the negative spike was very large.
The positive and negative impulse are now more in phase with c2=1nF.
C1 = 1.5nF its bigger as usual to mach the negative impulse. but by doing this it also loses some voltage.

L3 sees both the positive and the negative impulse.

If L2 is tuned into the res freq, the current is max, but there is no positive spike.

How i wish, I had a variable capacitor, to easily tune in the right capacitance. but thats not an option. Its tedious work....
Only negative impulse
« Reply #342,  »
Im starting to wonder...
do we really need the positive impulse?

its only there when l2 is detuned upward in frequency. That also lowers the current.

the negative impulse is always there, when l2 is fully tuned resonant. with all the current.

detuning l2 seems odd.

need to try and get max resonance, and make c2 even smaller then the 1nF I now have, so it will enter the sub 1uS range.
C1 could even change its value, bit ill leave it at 1.5nF for now.

Good thing is, when L2 is tuned, it reduces the l1 currentdraw from the powersupply, and thats good. maybe if c1 is slightly bigger, it drops the current even more.

l3 then shows the sine and current.
the sine on the positive max shows a negative impulse.
What would tuning l3 with c6 do with this?
only one way to find out.

Is the negative impulse still on the right side of l2? why does it show up on l3. thats weird.
as the l2 negative impulse is on the l1 side?
should I rewire it so it shows up on the l3 side?

Is the negative voltage impulse a presure or a vacuum?

Re: new oscillator circuit shared By Nelson Rocha
« Reply #343,  »
that positive impulse is only observed when the l2 is detuned upwards.
when tuned there stil is a small spike. so it probably is absorbed by the series resonance. giving power to the resonance.

makes sense.
Re: new oscillator circuit shared By Nelson Rocha
« Reply #344,  »
no c1 should stay small.
the impulse needs to feed the series resonamt c5 l2
if c1 is to big it absorbs the impulse energy
Re: new oscillator circuit shared By Nelson Rocha
« Reply #345,  »Last edited
just read info of james stephens.
makes a lot of sense.

the 2 blue coils with the white dielectric are at the hearth of nelsons radiant energy box.

I think each blue coil is a impulsed coil, together setting up a field in between them, through the white dielectric. its not a static field but a dynamic field. the field also moves through the blue coils and outside of it.
the coils outside of the blue (only one seen here, but he uses 2) pickup that streaming field.

Nelson probably does not realize, that without those outside pickup coils,
the 2 blue coils are by them self creating a rather unique field, able to influence:
gravity
time
mass

I have asked nelson about deviating smoke with these coils,
and he confirmed. stating he stopped smoken, but replaced it with an e vape.
He said the smoke did deviate when he worked with the coils.

he said, it was due to ionization. but I think there is a lot more going in...

what im saying, is I am right now working on one coil. The circuit could be altered to have 2 coils with the dynamic electric field between it. and have 2 output coils

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Matt Watts

Re: new oscillator circuit shared By Nelson Rocha
« Reply #346,  »
Do keep in mind each of those two coils can act like a capacitor plate.  And with a dielectric between them, it's not unlikely these fields charge that dielectric to extreme potentials.  The question you have to ask yourself is:  Do you discharge that dielectric, or do you keep in there for some other benefit?

evostars

Re: new oscillator circuit shared By Nelson Rocha
« Reply #347,  »
Quote from Matt Watts on January 6th, 02:51 AM
Do keep in mind each of those two coils can act like a capacitor plate.  And with a dielectric between them, it's not unlikely these fields charge that dielectric to extreme potentials.  The question you have to ask yourself is:  Do you discharge that dielectric, or do you keep in there for some other benefit?
You are talking about a static field, but I talk about a dynamic field between the two blue coils.
imagine the electric field being dynamic flowing from high dielectric flux to low dielectric flux inside the white dielectric.
then outside the coils, the electric fields close the loops forming a ring toroid. with the white dielectric beimg the center tube.

keep in mind its not static like a capacitor charged with a dielectric field. But its dynamic, due to the impulsed nature, pumping the aether around.
Re: new oscillator circuit shared By Nelson Rocha
« Reply #348,  »
want to try one more setup.
l1 l3 l2 stacked with ferrite rods in between.
Re: new oscillator circuit shared By Nelson Rocha
« Reply #349,  »
l1 l3 l2 stacked with ferrite rods in between does work pretty good.
L3 in the middle with a 42w 230V load does light up around 82 khz inductance of L3 is higher because its coupled to l1 and l2, via the ferrite rods. I measured 0.61mH for L3 (in center of stack)

let the tuning commence  :cheerleader:

again :fdrum: